Question

我的代码遇到问题，我想不出一种解决方法。

注意：我不允许在我的代码中使用导入

代码如下：

def decode(in_file, out_file):
    try:
        s = ""
        chr_nums = []
        splitlst = []
        lines = []
        lst = []
        f = open('q4.txt','r')
        for line in f:
            lines = line.split()
            for i in range(len(lines)):
                b = str(lines[i])
                for l in b:
                    chr_nums = chr(ord(l) - 1)
                    for a in chr_nums:
                        c =' '.join(a)
                        print c 

                    
    except IOError:
        print "Cant decipher' {"+in_file+"} 'due to an IO Error."
        f.close()

此代码的目标是将每个单词中的每个字母替换为之前的字母。即：将a更改为z，依此类推。

代码必须更改包含此类文本的文件：

Uif Xiffmt po uif cvt hp spvoe boe spvoe
Uif Xiffmt po uif cvt hp spvoe boe spvoe

此结果：

The Wheels on the bus go round and round
The Wheels on the bus go round and round

这是我的for循环在out_file中打印的内容：

T h e W h e e l s o n t h e b u s g o r o u n d a n d r o u n dT h e W h e e l s o n t h e b u s g o r o u n d a n d r o u n d

如何获得示例中显示的结果？如何重新加入角色以形成原始顺序？

note2：我确实尝试过使用join，但也没有运气

note3：代码获取的文件不一定包含两次相同的句子。

Answer 1

使用here所述的if/else in Python's list comprehension。

示例代码为

f = open('q4.txt','r')
for line in f:
    lst = list(line)
    lst2 = [chr(ord(x) - 1)  if x != ' ' else ' ' for x in lst]
    print("".join(lst2))

我得到以下输出

The Wheels on the bus go round and round    
The Wheels on the bus go round and round
[Finished in 0.1s]

Answer 2

除了弗朗西斯亲王的代码外，以下是采用您的代码风格的解决方案：

def decode(foo):
    final_string = ""
    f = foo
    for line in f:
        lines = line.split()
        for i in range(len(lines)):
            b = str(lines[i])
            for l in b:
                chr_nums = chr(ord(l) - 1)
                final_string += chr_nums
            final_string += " "
        final_string += "\n" # new line
    return(final_string)

secret_text = ["Uif Xiffmt po uif cvt hp spvoe boe spvoe", 
               "Uif Xiffmt po uif cvt hp spvoe boe spvoe"]

print(decode(foo=secret_text))

请注意，完全不需要“ try”之后的前五行。它们没有影响。其余的只是在适当的时候设置空格和换行符。

如何将每个字符更改为字符串中的每个字符并保持原始顺序python？

2 个答案: