Question

我有一个像这样的字符串：A =1 for (i in seq(0.1, 0.3 , by = 0.1)) { for (j in seq(0.1, 0.3, by = 0.1)) { for (k in seq(0.1, 0.3, by = 0.1)) { B = paste("a", i , "b", j, "c",k) A = c(A, B) } } } A = A[-1] A > A [1] "a 0.1 b 0.1 c 0.1" "a 0.1 b 0.1 c 0.2" "a 0.1 b 0.1 c 0.3" "a 0.1 b 0.2 c 0.1" "a 0.1 b 0.2 c 0.2" "a 0.1 b 0.2 c 0.3" [7] "a 0.1 b 0.3 c 0.1" "a 0.1 b 0.3 c 0.2" "a 0.1 b 0.3 c 0.3" "a 0.2 b 0.1 c 0.1" "a 0.2 b 0.1 c 0.2" "a 0.2 b 0.1 c 0.3" [13] "a 0.2 b 0.2 c 0.1" "a 0.2 b 0.2 c 0.2" "a 0.2 b 0.2 c 0.3" "a 0.2 b 0.3 c 0.1" "a 0.2 b 0.3 c 0.2" "a 0.2 b 0.3 c 0.3" [19] "a 0.3 b 0.1 c 0.1" "a 0.3 b 0.1 c 0.2" "a 0.3 b 0.1 c 0.3" "a 0.3 b 0.2 c 0.1" "a 0.3 b 0.2 c 0.2" "a 0.3 b 0.2 c 0.3" [25] "a 0.3 b 0.3 c 0.1" "a 0.3 b 0.3 c 0.2" "a 0.3 b 0.3 c 0.3" >

我想使用正则表达式从字符串中提取00:1E:AE:4F:20:0BDntl3l的mac地址，并丢弃00:1E:AE:4F:20:0B。我如何在C＃中实现呢？

我尝试了以下代码，但仍返回相同的字符串。

Dntl3l

Answer 1

以下对我有用：

google-services.json

但是我个人觉得这有点令人困惑，所以我会做这样的事情：

2018-12-06T17:50:11.193851+00:00 app[web.1]: I, [2018-12-06T17:50:11.193690 #4]  INFO -- : [0f0791d6-3aab-4f19-83ad-c421af4a0788] Started GET "/users/edit" for xx.xxx.xxx.xxx at 2018-12-06 17:50:11 +0000

编辑：或者，如果您将两者结合起来：

Started GET "/users/edit" for xx.xxx.xxx.xxx at 2018-12-06 17:50:11 +0000

编辑2：我又想出了另一种使用LINQ和var s = "DSz00:1E:AE:4F:20:0BDntl3l"; var macRegex = "([0-9A-Fa-f]{2}:){5}[0-9A-Fa-f]{2}"; var result = Regex.Match(s, macRegex); Console.WriteLine(result); // 00:1E:AE:4F:20:0B的{{1}}的方法，尽管我认为这是一个过大的技巧：

var s = "DSz00:1E:AE:4F:20:0BDntl3l";

var hexPair = "[0-9A-Fa-f]{2}";
var macRegex = $"{hexPair}:{hexPair}:{hexPair}:{hexPair}:{hexPair}:{hexPair}";
var result = Regex.Match(s, macRegex);

Console.WriteLine(result); // 00:1E:AE:4F:20:0B

从字符串中提取MAC地址

1 个答案: