Question

下面是我的代码...

from bs4 import BeautifulSoup

import requests


for count in range(1,2):


    r = requests.get('http://manufacturer.indiatradepage.com/all/a_a_enterprises/' + str(count) + '/',headers={'User-Agent': 'Googlebot'})

    soup = BeautifulSoup(r.text,'lxml')

    data = soup.find('div',class_='container_main')

    for links in data.find_all('div',class_='com_countainer'):
        for link in links.find_all('a')[0:1]:
            l = link['href']
            r = requests.get(l)
            soup = BeautifulSoup(r.text,'lxml')

            data = soup.find('td',{"id":"intro_txt"})
            table1 = data.find('table',{"style":"max-height: 400px !important"})

            body1 = table1.find('div',class_='f_body')


            table2 = data.find('div',{"id":"f3_1"})

            div = table2.find('div',class_='f_body')


            body2 = div.find('div',{"style":"text-transform:capitalize; "})

            print body2.text + body1.text

我收到以下错误消息。

回溯（最近通话最近）：文件 “ C：/Python27/indiatradepage_try.py”，第19行 body1 = table1.find（'div'，class _ ='f_body'）AttributeError：'NoneType'对象没有属性'find'

由于以下错误，我的代码每次都被破坏。

Answer 1

您可以通过不尝试在NoneType对象上使用属性.find来解决此问题，这是您在body1 = table1.find('div',class_='f_body')以及可能在table2 = data.find('div',{"id":"f3_1"})

您可以执行类似的操作，这将检查表是否为None，如果不是，则打印出该表不存在，而不是.find，然后继续循环。

from bs4 import BeautifulSoup

import requests


for count in range(1,2):

    r = requests.get('http://manufacturer.indiatradepage.com/all/a_a_enterprises/' + str(count) + '/',headers={'User-Agent': 'Googlebot'})

    soup = BeautifulSoup(r.text,'lxml')

    data = soup.find('div',class_='container_main')

    for links in data.find_all('div',class_='com_countainer'):
        for link in links.find_all('a')[0:1]:
            l = link['href']
            r = requests.get(l)
            soup = BeautifulSoup(r.text,'lxml')

            data = soup.find('td',{"id":"intro_txt"})
            table1 = data.find('table',{"style":"max-height: 400px !important"})

            if table1 != None:
                body1 = table1.find('div',class_='f_body').text
            else:
                body1 = ' table1 no present '


            table2 = data.find('div',{"id":"f3_1"})
            if table2 != None:
                div = table2.find('div',class_='f_body')
                body2 = div.find('div',{"style":"text-transform:capitalize; "}).text
            else:
                body2 = ' table2 not present '

            print (body2 + body1)

使用BeautifulSoup时出现“ NoneType”错误

1 个答案: