Question

我需要打印出十二个带有单词和频率（出现“单词”的次数）的文本文件，但这并不是要打印只出现一次的单词。我怎么不把那些话打印出来。我想知道如何基本能够使用向量的2nd值来做事。

#include <iostream>
#include <map>
#include <fstream>
#include <string>
#include<bits/stdc++.h>
#include <iterator>

using namespace std;

template <class KTy, class Ty>

void PrintMap(map<KTy, Ty> map)
{
    typedef typename  std::map<KTy, Ty>::iterator iterator;

    std::vector<std::pair<std::string,int>> vector( map.begin(), map.end() );

    std::sort( vector.begin(), vector.end(),
               []( const auto & lhs, const auto  rhs )
               { return lhs.second > rhs.second;} );

    for ( const auto & item : vector )
        if (item.second == 1)
            ::cout << item.first << ": " << item.second << std::endl;
}

int main(void)
{
    vector <string> File;
    File.push_back("data.txt");
    File.push_back("data_1.txt");
    File.push_back("data_2.txt");
    File.push_back("data_3.txt");
    File.push_back("data_4.txt");
    File.push_back("data_5.txt");
    File.push_back("data_6.txt");
    File.push_back("data_7.txt");
    File.push_back("data_8.txt");
    File.push_back("data_9.txt");

    map<string, unsigned int> wordsCount;

    for (int i=0; i < File.size(); i++)
    {
        ifstream fileStream(File[i]);

        if (fileStream.is_open())
            while (fileStream.good())
            {
                string word;
                fileStream >> word;

                if (wordsCount.find(word) == wordsCount.end())
                    wordsCount[word] = 1;
                else
                    wordsCount[word]++;
            }
            else
            {
                cerr << "ERROR." << endl;
                return EXIT_FAILURE;
            }
    }
    PrintMap(wordsCount);
    return EXIT_SUCCESS;
}

Answer 1

如果您不想打印仅出现一次的单词，请更改：

if (item.second == 1)

至：

if (item.second != 1)

如何不从向量C ++打印选定的元素

1 个答案: