Question

我在创建一个程序时遇到了麻烦，该程序将Array中的数字输入并通过字符串返回它们。我的

中的以下代码

main.m文件：

#import <Foundation/Foundation.h>
#import "NumberRepeater.h"

int main(int argc, const char * argv[]) {
    @autoreleasepool {
        NumberRepeater *repeater1 = [[NumberRepeater alloc] 
        initWithNumbers: @[@[@1, @10]]];

        [repeater1 initWithNumbers:@[@[@1, @10]]];
        NSLog(@"%@", [repeater1 process]);

        NumberRepeater *repeater2 = [[NumberRepeater alloc] 
        initWithNumbers: @[@[@1, @2], @[@2, @3]]];

        NSLog(@"%@", [repeater2 process]);

        NumberRepeater *repeater3 = [[NumberRepeater alloc] 
        initWithNumbers: @[@[@10, @4], @[@34, @6], @[@92, @2]]];

        NSLog(@"%@", [repeater3 process]);
    }
    return 0;
}

NumberRepeater.h文件中的代码：

#import <Foundation/Foundation.h>

NS_ASSUME_NONNULL_BEGIN

@interface NumberRepeater : NSObject
- (instancetype)initWithNumbers:(NSArray *)numbers;

- (NSString *)process;


@end

NS_ASSUME_NONNULL_END

NumberRepeater.m文件中的代码：

#import <Foundation/Foundation.h>
#import "NumberRepeater.h"
@implementation NumberRepeater

- (instancetype)initWithNumbers:(NSArray *)numbers {
    NumberRepeater *repeater1 = [[NumberRepeater alloc] 
initWithNumbers: @[@[@1, @10]]];
    [repeater1 initWithNumbers:@[@[@1, @10]]];
    NSLog(@"%@", repeater1);

    return 0;
}

- (NSString *)process {


    return 0;
}

@end

我的预期输出应为：

1111111111
11, 222
10101010, 343434343434, 9292

这绝不是我需要解决的学校作业。我希望有一个解决方案，但是对此的指导会很棒。我做完类似的问题并获得所需的输出后，就快要拥有它了，但显然我很想念，我只是不知道是什么。我了解我的处理方法缺少代码，只是我不完全知道该放在哪里。任何帮助将不胜感激！

Answer 1

•我需要根据您的问题为您解释数组语法，

首先，您可以以这种方式@[@1,@2,....]声明NSNumber的数组对象为Int值，因为数组仅包含id对象，因此我们不能直接使用Int，而是使用NSnumber @ 1
数组内的对象可以是Array本身，因此我们可以声明数组对象的数组 像这个例子@[@[@10, @4], @[@3, @6], @[@2, @9]]这样的数组数组 @[@[],@[],....etc]

•根据您的问题，我给您NSArray两件只需给我一个字符串，其中第一项重复（第二项）次

   Example :

        Input @[@1,@2]      repeat number#1  two times
        Output should be 11

        Input @[@1,@10]      repeat number#1  10 times
        Output should be 1111111111

       Input @[@[@1,@3],@[@3,@4]]      repeat number#1  3 times , number#3   4 time
        Output should be 111 3333

解决方案

NumberRepeater.h

#import <Foundation/Foundation.h>

NS_ASSUME_NONNULL_BEGIN

@interface NumberRepeater : NSObject {
      NSArray * numbers; // private number array will be initialized during initialization of object
}
- (instancetype)initWithNumbers:(NSArray *)numbers;

- (NSString *)process;
@end

NS_ASSUME_NONNULL_END

NumberRepeater.m

#import "NumberRepeater.h"
#import <Foundation/Foundation.h>


// NumberRepeater Extention for set private numbers
@interface NumberRepeater ()
@property (nonatomic,retain) NSArray *numbers;
@end


@implementation NumberRepeater
@synthesize numbers;

- (instancetype)initWithNumbers:(NSArray *)numbers {

    self = [super init];
    if (self) {
        self.numbers = numbers;
    }
    return self;
}

- (NSString *)process {

// if numbers have No Data
   if (numbers.count == 0) { return  @"0"; }

    // Array of array  each array have two element first is number to repeat and second have number of repetation
    // Example @[@1, @2]   repeat number(1)   TWO times  so out put should be 11
 //   @[@[@1, @2], @[@2, @3]]

    NSMutableString * output = [NSMutableString new];

    for (NSArray*item in numbers) {

        // Array should be with this Format
          // Example @[@1, @2]   repeat number(1)   TWO times

              // assert item have tow items only  like that @[@1,@2]
           NSAssert(item.count == 2,@"Array Should have Two items only");

        NSNumber *numberToRepeat = item[0]; // repeat
        NSNumber *repetitionCount = item[1]; //repetition Count

        NSMutableString * repeatdString = [NSMutableString new];

        for (NSInteger i= 0; i < [repetitionCount integerValue] ; i++) {
            [repeatdString appendString:[numberToRepeat stringValue]];
        }

        [output appendString:repeatdString];
        [output appendFormat:@" "]; // space on join with muti array

    }


    return output;
}
@end

main.m

#import <Foundation/Foundation.h>
#import "NumberRepeater.h"

int main(int argc, const char * argv[]) {
    @autoreleasepool {
        NumberRepeater *repeater1 = [[NumberRepeater alloc] 
        initWithNumbers: @[@[@1, @10]]];

        NSLog(@"%@", [repeater1 process]);

        NumberRepeater *repeater2 = [[NumberRepeater alloc] 
        initWithNumbers: @[@[@1, @2], @[@2, @3]]];

        NSLog(@"%@", [repeater2 process]);

        NumberRepeater *repeater3 = [[NumberRepeater alloc] 
        initWithNumbers: @[@[@10, @4], @[@34, @6], @[@92, @2]]];

        NSLog(@"%@", [repeater3 process]);
    }
    return 0;
}

Answer 2

我无法正确理解您的问题，但我想您需要一个函数，该函数接受参数为数字的数组，并返回由所有数字组合而成的字符串，如果您想要的话，您可以创建这样的函数：-

-(NSString *)getStringFromArray:(NSArray <NSNumber *> *)array{
    NSString *numberString = @"";
    for (NSNumber *no in array) {
        numberString = [numberString stringByAppendingString:no.stringValue];
    }
    return numberString;
}

像这样调用类中的方法：-

NSLog(@"Number String %@",[self getStringFromArray:@[@1,@2,@3,@4]]);

输出

Number String 1234

重复数字数组

2 个答案: