Question

我已经在JPA存储库中定义了此查询

  @org.springframework.data.jpa.repository.Query("select min(cur.volumeUsd24h), max(cur.volumeUsd24h), "
        + "min(marketCapUsd),       man(marketCapUsd), "
        + "min(availableTickets),   man(availableTickets), "
        + "min(totalTickets),       man(totalTickets)  "
        + "min(maxTickets),             man(maxTickets)  "
        + "from Tickets cur  ")
  Object[] findQueryFiltersValues ();

但是当我启动应用程序时，出现此错误：

Caused by: java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token: min near line 1, column 211 [select min(cur.volumeUsd24h), max(

我也尝试过

@Query(value = "select min(cur.volume_usd_24h), max(cur.volume_usd_24h), "
        + "min(market_cap_usd),       max(market_cap_usd), "
        + "min(available_tickets),   max(available_tickets), "
        + "min(total_tickets),       max(total_tickets)  "
        + "min(max_tickets),             max(max_tickets)  "
        + "from tickets cur  ",nativeQuery = true)

但是出现编译错误：

Multiple markers at this line
    - Syntax error on token ",", [ expected
    - Syntax error, insert "]" to complete 
     Expression

Answer 1

假设man实际上是max，则原始查询具有语法错误，这就是异常的原因。 max(totalTickets)之后没有没有逗号，这使得查询max(totalTickets) min(maxTickets)。根据发布的代码查看this sample，该代码显示了已执行的更正查询

Answer 2

JPA存储库不支持最小，最大功能。

您应该将查询更改为本地sql（将POJO字段替换为数据库列名称）

并添加nativeQuery = true属性。

类似这样的东西

@Query(value = "select min(cur.volume_usd_24h), max(cur.volume_usd_24h), "
        + "min(market_cap_usd),       max(market_cap_usd), "
        + "min(available_tickets),   max(available_tickets), "
        + "min(total_tickets),       max(total_tickets)  "
        + "min(max_tickets),             max(max_tickets)  "
        + "from tickets cur  ",nativeQuery = true)

QuerySyntaxException：意外令牌

2 个答案: