为“设置”页面创建活动后,我注意到mCurrentValue !== value
中的if (mCurrentValue !== value)
返回了警告:
布尔型参数的身份相等性?和布尔值可能会由于隐式拳击而变得不稳定
我尝试通过在?
中的Boolean
旁边添加override fun onXchange(value:Boolean) {
来解决此警告,但随后返回以下错误:
'onXchange'不会覆盖任何内容
关于如何解决此问题的任何想法?
活动课程
import android.content.Intent
import android.graphics.Color
import android.graphics.drawable.ColorDrawable
import android.os.Bundle
import android.preference.PreferenceManager
import android.support.v7.app.AppCompatActivity
import android.view.MenuItem
class MySettingsActivity : AppCompatActivity(), MySettingsFragment.PreferenceXchangeListener {
private var mCurrentValue: Boolean? = null
override fun onCreate(savedInstanceState: Bundle?) {
val mSharedPreferences = PreferenceManager.getDefaultSharedPreferences(this)
mCurrentValue = mSharedPreferences.getBoolean("preference_a", false)
if (mCurrentValue as Boolean)
{
setTheme(R.style.MyDarkAppCompatTheme)
}
else
{
setTheme(R.style.MyLightAppCompatTheme)
}
super.onCreate(savedInstanceState)
setContentView(R.layout.activity_mysettings)
val settingsFragment = MySettingsFragment()
supportFragmentManager
.beginTransaction()
.replace(R.id.settings_container, settingsFragment)
.commit()
val myActionBar = actionBar
if (myActionBar != null)
{
myActionBar.setTitle(R.string.settings)
myActionBar.setBackgroundDrawable(ColorDrawable(Color.BLACK))
myActionBar.setDisplayHomeAsUpEnabled(true)
myActionBar.setDisplayShowHomeEnabled(true)
myActionBar.setHomeAsUpIndicator(resources.getDrawable(R.drawable.ic_arrow_back_white, null))
}
}
override fun onXchange(value:Boolean?) {
if (mCurrentValue !== value) {
mCurrentValue = value
recreate()
}
}
override fun onOptionsItemSelected(item: MenuItem): Boolean {
when (item.itemId) {
android.R.id.home -> {
val intent = parentActivityIntent
intent?.addFlags(Intent.FLAG_ACTIVITY_NO_ANIMATION)
onBackPressed()
return true
}
else ->
return super.onOptionsItemSelected(item)
}
}
}
片段类
class MySettingsFragment : PreferenceFragmentCompat(), Preference.OnPreferenceChangeListener {
override fun onCreatePreferences(savedInstanceState: Bundle?, rootKey: String?) {
addPreferencesFromResource(R.xml.app_preferences)
val mCheckBoxPreference = findPreference("preference_a") as CheckBoxPreference
mCheckBoxPreference.onPreferenceChangeListener = this
}
private var mPreferenceXchangeListener: PreferenceXchangeListener? = null
interface PreferenceXchangeListener {
fun onXchange(value:Boolean)
}
override fun onAttach(context: Context) {
super.onAttach(context)
try
{
mPreferenceXchangeListener = context as MySettingsFragment.PreferenceXchangeListener
}
catch (e:ClassCastException) {
Log.e(TAG, "onAttach::::: PreferenceXchangeListener must be set in parent Activity")
}
}
override fun onPreferenceChange(preference: Preference, newValue:Any):Boolean {
val preferenceKey = preference.key
if (preferenceKey == "preference_a")
{
(preference as CheckBoxPreference).isChecked = newValue as Boolean
mPreferenceXchangeListener!!.onXchange(newValue)
return true
}
return false
}
companion object {
private val TAG = MySettingsFragment::class.java.simpleName
}
}
答案 0 :(得分:2)
所以首先我可以解释它描述的问题。让我们提出一个非常人为的方案:
BooleanProvider.java
class BooleanProvider {
@NonNull Boolean wrapMyBoolean(boolean state) {
return new Boolean(state);
}
}
BooleanProviderTest.kt
class BooleanProviderTest {
@Test fun `it returns a true value when true is provided`() {
assertSame(BooleanProvider().wrapMyBoolean(true), true)
}
}
该测试实际上将失败,因为Boolean
的实例不相同。在Java代码中,我们初始化了Boolean
的新实例(而不是将原语自动装箱到{{时会得到的静态定义的Boolean.TRUE
和Boolean.FALSE
实例)。 1}})。因此,为避免潜在的意外结果,建议您不要通过引用比较这些类型。
最简单的解决方法是将相等性测试更改为java.lang.Boolean
而不是!=
。这将执行身份相等性测试,而不是引用相等性测试,并且将在任一端适当地处理null值。无论如何,这就是您想要的99%的时间。
第二,如果不需要以特定方式处理null值,则也可以只将!==
声明为非null类型,并为其提供默认值。只需将其声明为:
mCurrentValue