Question

我目前正在为一个简单的Python课程进行决赛，但是我似乎遇到了一些很奇怪的事情。目的是创建一个具有错误异常检查功能的菜单，并允许用户启动预定义功能。 EXCEPT 对于drawKochFractal函数来说一切正常。

似乎可以编译并完全正常运行，而且我知道逻辑和数学是正确的。我什至添加了打印语句，以检查它在控制台中的位置，并且它正在确定运行。但是在画布窗口上什么也没有绘制或显示！我是否忽略了某些内容，或者可能是我自己的python环境？谢谢！

elif select == 3:
            #Koch Function:
            """
            File: koch.py
            Project 7.3

            This program displays a Koch snowflake using
            the user's input level.
            """
            def drawKochFractal(width, height, size, level):
                """Draws a Koch fractal of the given level and size."""
                t.screen.colormode(255)
                t.pencolor(random.randint(1, 255),
                random.randint(1, 255),
                random.randint(1, 255))
                t.up()
                t.goto(-width // 3, height // 4)
                t.down()
                print("I am the begin")
                drawFractalLine(t, size, 0, level);
                print("I am here")
                drawFractalLine(t, size, -120, level)
                drawFractalLine(t, size, 120, level)

            def drawFractalLine(t, distance, theta, level):
                """Either draws a single line in a given direction
                or four fractal lines in new directions."""
                if (level == 0):
                    drawPolarLine(t, distance, theta)
                else:
                    drawFractalLine(t, distance // 3, theta, level - 1)
                    drawFractalLine(t, distance // 3, theta + 60, level - 1)
                    drawFractalLine(t, distance // 3, theta - 60, level - 1)
                    drawFractalLine(t, distance // 3, theta, level - 1)
                    print("I am here too!")

            def drawPolarLine(t, distance, theta):
                """Moves the given distance in the given direction."""
                t.setheading(theta)
                print("im turning!")
                t.forward(distance)

            width = input("Enter the width: ")
            height = input("Enter the height: ")
            size = input("Enter the size value: ")
            level = input("Enter the level (0 - 10): ")
            t = Turtle()
            t.hideturtle()
            t.screen.clear()
            #Let's make sure these variables are calculatable!
            try:
                width = int(width)
                height = int(height)
                size = int(size)
                level = int(level)
            except:
                print("####Invalid Response####")
                #If parameters do not work, send back to home menu
                main()
            #If level is not in correct range, send back to home menu with error response:
            if level > 10 or level < 0:
                print("####Level must be between 0 and 10####")
                main()
            #create drawKochFractal with user parameters, then take back to home menu:
            drawKochFractal(width, height, size, level)
            print("####Koch Fractal Complete! Taking you back to the main menu...####")
            main()

Answer 1

问题在这里：

t = Turtle()
t.hideturtle()
t.screen.clear()

屏幕的clear()方法会损坏现有的用户乌龟，并重新创建默认的乌龟。我建议您尝试：

from turtle import Screen, Turtle

# ...

screen = Screen()
screen.clear()
t = Turtle()
t.hideturtle()

也就是说，在清除屏幕后创建乌龟，并且不要使用乌龟访问屏幕clear()方法，而应使用指向单个屏幕实例的独立指针。

Turtle代码已执行，但未在画布中绘制

1 个答案: