我在垂直LinearLayout中有3个TextView,如下所示:
<?xml version="1.0" encoding="utf-8"?>
<android.support.constraint.ConstraintLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="@color/green"
tools:context=".SplashActivity">
<LinearLayout
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical"
android:gravity="center">
<TextView
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:textColor="@android:color/white"
android:gravity="center"
android:text="FirstText"/>
<TextView
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:textColor="@android:color/white"
android:gravity="center"
android:text="Second"/>
<TextView
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:textColor="@color/lightGray"
android:gravity="center"
android:text="ThirdText"/>
</LinearLayout>
</android.support.constraint.ConstraintLayout>
以上代码的当前输出:
但是我希望文本像这样彼此左对齐:
我该如何实现?
答案 0 :(得分:1)
您需要有一个顶级父级,以其内容为中心。在其中,您将拥有一个中级父级,该父级将其内容左对齐。在其中,您将拥有三个TextView。
完成这项工作的关键是使中级父级仅与其内容一样宽。这样,最大的子项将定义中级父项的总体大小,然后顶级父项可以将它们的组居中。
<FrameLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent">
<LinearLayout
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:orientation="vertical"
android:layout_gravity="center">
<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="FirstText"/>
<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Second"/>
<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="ThirdText"/>
</LinearLayout>
</FrameLayout>
答案 1 :(得分:-1)
library(stats)
my_data = data.frame(
success=c(1, 0, 1, 1, 0, 0, 1, 1, 0, 1),
col_a=c(5000.0, 10000.0, 11000.0, 20000.0, 20000.0, 25000.0, 30000.0, 30000.0, 40000.0, 41000.0),
col_b=c('a', 'a', 'b', 'b', NA, 'b', 'c', 'c', NA, 'd'),
col_c=c(5487.0, 5654.0, NA, 2918, 912.0, NA, 1236.0, 234.0, 2390.0, 21092.0)
)
myFormula <- stats::formula(paste0("success ~ col_a + col_b + col_c"))
fit <- stats::glm(myFormula, data=my_data, family=stats::binomial(link="logit"), na.action=stats::na.exclude)
summary(fit)
Call:
stats::glm(formula = myFormula, family = stats::binomial(link = "logit"),
data = my_data, na.action = stats::na.exclude)
Deviance Residuals:
[1] 0 0 0 0 0 0
Coefficients:
Estimate Std. Error z value Pr(>|z|)
(Intercept) 7.370e+01 1.026e+06 0 1
col_a -9.826e-03 3.757e+01 0 1
col_bb 1.474e+02 7.500e+05 0 1
col_bc 2.457e+02 1.334e+06 0 1
col_bd 3.538e+02 2.943e+06 0 1
col_c 3.282e-12 1.849e+02 0 1
(Dispersion parameter for binomial family taken to be 1)
Null deviance: 5.4067e+00 on 5 degrees of freedom
Residual deviance: 2.5720e-10 on 0 degrees of freedom
(4 observations deleted due to missingness)
AIC: 12
Number of Fisher Scoring iterations: 23