Question

我的angularjs应用中有一个复选框作为过滤器：

这是我的数据：

app.controller('listdata', function($scope, $http) {
$scope.users = [{
    "name": "pravin",
    "queue": [{
        "number": "456",
        "status": "Unavailable"
    }],
    "phone": "7411173737"
},
{
    "name": "pratik",
    "queue": [{
        "number": "111",
        "status": "Unavailable"
    }],
    "phone": "8558855858"
},
{
    "name": "priyanka",
    "queue": [{
        "number": "111",
        "status": "Unavailable"
    }],
    "phone": "5454573737"
},
{
    "name": "prerana",
    "queue": [{
        "number": "111",
        "status": "Unavailable"
    }],
    "phone": "7454543737"
}];

});

我在这样的视图中显示上述数据：

//这是过滤器

<label class="switch">
  <input ng-true-value='111' ng-false-value='' type="checkbox" ng-model="queue111">111
</label>

// ng重复部分

<div class="row" ng-controller="listdata">
    <div ng-repeat="user in users|filter:queue111">
       <p> {{user.name}} {{user.phone}}</p>
    </div>
</div>

启动应用程序时，将显示用户数据阵列中的所有四个用户。当我单击过滤器复选框时，它将显示队列中包含数字111的用户。但是由于包含电话号码7411173737（其中包含111），它还会显示用户pravin。我希望此过滤器仅显示其队列编号的记录与111匹配，而不与此处的电话号码等任何其他字段匹配。因此，筛选器应仅显示队列号为111的记录。

是否可以做类似

的操作

<input ng-true-value='111' ng-false-value='' type="checkbox" ng-model="queue111.queue.number">111

当前输出：它显示$ scope.users中的所有四个数据对象

预期输出：仅显示队列编号中的数据对象   $ scope.users中是111

我该怎么做？

Answer 1

尝试使用此自定义过滤器功能以仅匹配队列数组中的值。

var Controller = function($scope) {
  $scope.users = [{
      "name": "pravin",
      "queue": [{
        "number": "456",
        "status": "Unavailable"
      }],
      "phone": "7411173737"
    },
    {
      "name": "pratik",
      "queue": [{
        "number": "111",
        "status": "Unavailable"
      }],
      "phone": "8558855858"
    },
    {
      "name": "priyanka",
      "queue": [{
        "number": "111",
        "status": "Unavailable"
      }],
      "phone": "5454573737"
    },
    {
      "name": "prerana",
      "queue": [{
        "number": "111",
        "status": "Unavailable"
      }],
      "phone": "7454543737"
    }
  ];

  $scope.filter = function(item) {
    if ($scope.queue111) {
      return JSON.stringify(item.queue).includes($scope.queue111);
    } else {
      return true;
    }
  };

};

angular
  .module('app', [])
  .controller('Controller', Controller);

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="app" ng-controller="Controller">
  <label class="switch">
    <input ng-true-value='111' ng-false-value='' type="checkbox" ng-model="queue111">
  </label>
  <pre>Search value: {{queue111}}</pre>
  <div ng-repeat="user in users | filter:filter">
    {{user.name}} {{user.phone}}
  </div>
</div>

Answer 2

我通过在过滤器中使用自定义函数和三元运算符来修复了该问题：

var app = angular.module('myApp', []);

app.controller('listdata', function($scope, $http) {
$scope.users = [{
    "name": "pravin",
    "queue": [{
        "number": "456",
        "status": "Unavailable"
    }],
    "phone": "7411173737"
},
{
    "name": "pratik",
    "queue": [{
        "number": "111",
        "status": "Unavailable"
    },
    {
        "number": "112",
        "status": "Unavailable"
    }],
    "phone": "8558855858"
},
{
    "name": "priyanka",
    "queue": [{
        "number": "111",
        "status": "Unavailable"
    }],
    "phone": "5454573737"
},
{
    "name": "prerana",
    "queue": [{
        "number": "111",
        "status": "Unavailable"
    }],
    "phone": "7454543737"
}];
   $scope.filter111 = function (user) {
            return (user.queue.find(({number}) => number === '111'));
        }
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/angular.js/1.7.0/angular.min.js"></script>
<div ng-app="myApp">

<label class="switch">
  <input type="checkbox" ng-model="queue111">111
</label>


<div class="row" ng-controller="listdata">

  <div ng-repeat="user in users|filter: queue111? filter111: ''">
    <p> {{user.name}} {{user.phone}}</p>
  </div>
</div>

</div>

Answer 3

您可以将true传递给过滤器以启用严格匹配。

<div ng-repeat="user in users|filter:queue111:true">

angularjs过滤器仅返回完全匹配的值

3 个答案: