Question

我想创建一个mysql表，其所有字段均为php变量。为什么执行此代码时出错？

$stmttt = $pdo->query("
    CREATE TABLE $test (
    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
    $name VARCHAR(60) NOT NULL,
    $tel VARCHAR(30) NOT NULL,
    $email VARCHAR(50) NOT NULL,
    $city VARCHAR(50),
    CMSdate TIMESTAMP)
    ");

Answer 1

您可以使用{}正确地转义变量。尝试

$stmttt = $pdo->query("
    CREATE TABLE ${test} (
    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
    ${name} VARCHAR(60) NOT NULL,
    ${tel} VARCHAR(30) NOT NULL,
    ${email} VARCHAR(50) NOT NULL,
    ${city} VARCHAR(50),
    CMSdate TIMESTAMP)
");

还可以查看一个有效的示例here

创建一个具有php变量字段的php和mysql表

1 个答案: