Question

在尝试使用Xquery解析xml时，出现以下异常， javax.xml.xquery.XQException：不得以大小写的任何组合将处理指令命名为“ xml”。第1行第1行在{... rsion =“ 1.0” encoding =“ UTF-8 ...}附近的语法错误 XPST0003：不得以高位和高位的任何组合将处理指令命名为“ xml” 小写。下面给出的是XML文件。有人可以建议在这里做什么。

<?xml version="1.0" encoding="UTF-8"?>

<bookstore>

<book category="COOKING">
  <title lang="en">Everyday Italian</title>
  <author>Giada De Laurentiis</author>
  <year>2005</year>
  <price>30.00</price>
</book>

<book category="CHILDREN">
  <title lang="en">Harry Potter</title>
  <author>J K. Rowling</author>
  <year>2005</year>
  <price>29.99</price>
</book>

</bookstore>

Answer 1

我认为您在期望XQuery文件时已经向XQuery处理器提供了XML文件。 XML中的大多数内容在XQuery中也有效，但是XML声明是一个例外。（除了不允许使用名为“ xml”的处理指令外，这将被视为处理指令。）

检查如何调用XQuery处理器。您正在提供一个期望查询的XML数据文件。

Answer 2

尝试一下，

XQueryMain.java（java）

The form: 
  <form action="*/myobject/mymethod/uploadFile" method="post" enctype="multipart/form-data">
      <label for="exampleInputFile">File input</label>
      <input type="file" id="file" name="file">
      <p class="help-block">Upload a file to link.</p>
          <input type="text" name="myId" id="myId" value="{{theId}}" style="display:none;">
          <button type="submit" name="submit" value="Upload File" class="btn btn-primary"> 
              <span class="glyphicon glyphicon-upload"></span> Upload File 
          </button>
  </form>


My PHP method
public static uploadFile()
{
    there are calls to various methods that do the actual upload. These methods can return 
    errors if something caused the upload to not work properly. 

    If I want to return an error to display to the user do I:
       return "File did not upload";
    or
       return 'error';

    If no errors and all went well, I would like a message displayed to say it was successful.
}

condition.xqy（XQuery）

import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.InputStream;
import javax.xml.xquery.XQConnection;
import javax.xml.xquery.XQDataSource;
import javax.xml.xquery.XQException;
import javax.xml.xquery.XQPreparedExpression;
import javax.xml.xquery.XQResultSequence;
import com.saxonica.xqj.SaxonXQDataSource;

public class XQueryMain {
   public static void main(String[] args){
      try {
          InputStream inputStream = new FileInputStream(new File("condition.xqy"));
          XQDataSource dataSource = new SaxonXQDataSource();
          XQConnection connection = dataSource.getConnection();
          XQPreparedExpression preparedExpression = connection.prepareExpression(inputStream);
          XQResultSequence resultSequence = preparedExpression.executeQuery();

          while (resultSequence.next()) {
             System.out.println(resultSequence.getItemAsString(null));
          }
      }
      catch (FileNotFoundException | XQException e) {
         e.printStackTrace();
      }
   }
}

bookstore.xml（XML）

for $x in doc("bookstore.xml")/bookstore/book
where $x/price=30
return $x/title

将以下jar文件（SaxonHE9-9-0-2J）添加到类路径

saxon9he.jar
saxon9-test.jar
saxon9-xqj.jar

无法解析javax.xml.xquery.XQException

2 个答案: