Question

下面的代码给出错误，因为未定义“星期五”。如果缺少任何内容，请帮我。另外，如果我将'friday'和'prev_day'变量的位置与其他位置交换，则会收到未定义'prev_day'的错误消息。

import unittest
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
import datetime


d = datetime.date.today()

if d.weekday() == 0:
    tdelta = datetime.timedelta(days=3)
    friday = d - tdelta


elif d.weekday() in range(1,5):
    tdelta1 = datetime.timedelta(days=1)
    prev_day = d - tdelta1


class ClassName(unittest.TestCase):

    def setUp(self):

        self.driver = webdriver.Chrome(executable_path="C:\\Users\sameerj\IdeaProjects\chromedriver.exe")


    def test_as_on_date(self):

        driver = self.driver
        driver.maximize_window()
        driver.get("website")
        login = driver.find_element_by_id("Email")
        login.send_keys("email")
        password = driver.find_element_by_id("Password")
        password.send_keys("password")
        password.send_keys(Keys.ENTER)
        driver.find_element_by_id("menu_name").click()
        driver.find_element_by_partial_link_text("page name").click()
        date = driver.find_element_by_id("lblAsOn").text
        new = datetime.datetime.strptime(date,'%m/%d/%Y')
        data_date = new.date()

        if data_date == friday:
            print("Data as on", friday, "for page name")
        elif data_date == prev_day:
            print("Data as on", prev_day, "for page name")
        else:
            print("Data update required.")
        driver.close()


if __name__ == '__main__':
    unittest.main()

Answer 1

这是常见的错误类型

让我来分解你的错误

if d.weekday() == 0:
    tdelta = datetime.timedelta(days=3)
    friday = d - tdelta


elif d.weekday() in range(1,5):
    tdelta1 = datetime.timedelta(days=1)
    prev_day = d - tdelta1

如果我们执行您的程序

如果d.weekday() == 0持有假

然后它将转到

elif d.weekday() in range(1,5):

但您的friday = d - tdelta处于if状态。这就是为什么它显示错误

解决方案，您必须在friday条件之外定义if，并在if条件中重新分配值

您可以这样解决

friday = None
prev_day = None
d = datetime.date.today()

if d.weekday() == 0:
    tdelta = datetime.timedelta(days=3)
    friday = d - tdelta


elif d.weekday() in range(1,5):
    tdelta1 = datetime.timedelta(days=1)
    prev_day = d - tdelta1

Answer 2

new = datetime.datetime.strptime(date,'%m/%d/%Y')
data_date = new.strftime("%A")

这将为您提供一天的名称（例如：星期五），然后您可以根据自己的情况进行比较，

if data_date == "Friday":
        print("Data as on",data_date , "for page name")

对于前几天的比较，您必须这样做

tdelta1 = datetime.timedelta(days=1) prev_day = (new - tdelta1).strftime("%A")

在做之前，

elif data_date == prev_day:
        print("Data as on", prev_day, "for page name")

当使用prev_day替换Friday时，由于python解释器首先找到未定义的变量而出现错误。

Answer 3

您最好写：

d = datetime.date.today()

if d.weekday() == 0:
    tdelta = datetime.timedelta(days=3)
    prev_day = None
    friday = d - tdelta
elif d.weekday() in range(1, 5):
    tdelta1 = datetime.timedelta(days=1)
    prev_day = d - tdelta1
    friday = None

我对您的建议是使用Python IDE，它们会突出显示此类错误。

我还认为可以使用calendar模块进行检查

硒python中的datetime抛出错误

3 个答案: