我在自定义ProfileController中有一个构造函数和路由
private $userManager;
public function __construct(UserManagerInterface $userManager)
{
$this->userManager = $userManager;
}
/**
* @Route("/profile/bookings", name="profile_bookings")
*/
public function bookings()
{
$user = $this->getUser();
return $this->render('profile/bookings/bookings.html.twig', array('user'=>$user));
}
在我的模板中我引用
{{user.first_name}}
但是我得到了错误:
HTTP 500内部服务器错误 属性“ first_name”或方法“ first_name()”,“ getfirst_name()” /“ isfirst_name()” /“ hasfirst_name()”或“ __call()”都不存在,并且在类“ App \”中没有公共访问权限实体\用户”。
如何从数据库获取用户信息并显示在个人资料的子页面中?
编辑:用户实体...
<?php
namespace App\Entity;
use Doctrine\Common\Collections\ArrayCollection;
use Doctrine\Common\Collections\Collection;
use Doctrine\ORM\Mapping as ORM;
use FOS\UserBundle\Model\User as BaseUser;
/**
* @ORM\Entity
* @ORM\Table(name="`user`")
*/
class User extends BaseUser
{
/**
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
* @ORM\Column(type="integer")
*/
protected $id;
/**
* @ORM\Column(type="string", length=190)
*/
private $first_name;
/**
* @ORM\Column(type="string", length=190)
*/
private $last_name;
/**
* @ORM\Column(type="string", length=190, nullable=true)
*/
private $phone_number;
/**
* @ORM\Column(type="integer", nullable=true)
*/
private $profile_height;
/**
* @ORM\Column(type="integer", nullable=true)
*/
private $profile_weight;
/**
* @ORM\Column(type="date", nullable=true)
*/
private $profile_dob;
/**
* @ORM\Column(type="string", length=190, nullable=true)
*/
private $profile_gender;
/**
* @ORM\OneToMany(targetEntity="App\Entity\Booking", mappedBy="user")
*/
private $bookings;
public function __construct()
{
parent::__construct();
$this->bookings = new ArrayCollection();
}
/**
* Overridde setEmail method so that username is now optional
*
* @param string $email
* @return User
*/
public function setEmail($email)
{
$this->setUsername($email);
return parent::setEmail($email);
}
public function getFirstName()
{
return $this->first_name;
}
public function setFirstName($first_name)
{
$this->first_name = $first_name;
}
public function getLastName()
{
return $this->last_name;
}
public function setLastName($last_name)
{
$this->last_name = $last_name;
}
public function getPhoneNumber(): ?string
{
return $this->phone_number;
}
public function setPhoneNumber(string $phone_number): self
{
$this->phone_number = $phone_number;
return $this;
}
public function getProfileHeight(): ?int
{
return $this->profile_height;
}
public function setProfileHeight(?int $profile_height): self
{
$this->profile_height = $profile_height;
return $this;
}
public function getProfileDob(): ?\DateTimeInterface
{
return $this->profile_dob;
}
public function setProfileDob(?\DateTimeInterface $profile_dob): self
{
$this->profile_dob = $profile_dob;
return $this;
}
public function getProfileWeight(): ?int
{
return $this->profile_weight;
}
public function setProfileWeight(?int $profile_weight): self
{
$this->profile_weight = $profile_weight;
return $this;
}
public function getProfileGender(): ?string
{
return $this->profile_gender;
}
public function setProfileGender(?string $profile_gender): self
{
$this->profile_gender = $profile_gender;
return $this;
}
/**
* @return Collection|Booking[]
*/
public function getBookings(): Collection
{
return $this->bookings;
}
public function addBooking(Booking $booking): self
{
if (!$this->bookings->contains($booking)) {
$this->bookings[] = $booking;
$booking->setUser($this);
}
return $this;
}
public function removeBooking(Booking $booking): self
{
if ($this->bookings->contains($booking)) {
$this->bookings->removeElement($booking);
// set the owning side to null (unless already changed)
if ($booking->getUser() === $this) {
$booking->setUser(null);
}
}
return $this;
}
}
谢谢。
答案 0 :(得分:1)
只需在您的树枝模板中使用:
{{ user.getFirstName }}
工作正常。通常,Twig在PHP层上所做的工作非常简单:
check if user is an array and first_name a valid element; if not, and if user is an object, check that first_name is a valid property; if not, and if user is an object, check that first_name is a valid method (even if first_name is the constructor - use __construct() instead); if not, and if user is an object, check that getfirst_name is a valid method; if not, and if user is an object, check that isfirst_name is a valid method; if not, and if user is an object, check that hasfirst_name is a valid method; if not, return a null value.
请参见Twig variables。
通过这种方式,您应该对变量遵循Symfony Coding Standard,因为树枝很难找到用snake_case编写的属性的值。
答案 1 :(得分:1)
我不认为您应该在控制器中构造UserManagerInterface
。另外,就像弗兰克(Franck)所说的那样,如果可以的话,请使用编码标准,这将节省很多时间和麻烦!
这是我在Symfony 4项目中使用的控制器:
namespace App\Controller;
use FOS\UserBundle\Model\UserInterface;
use Symfony\Component\Routing\Annotation\Route;
use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use Symfony\Component\Security\Core\Exception\AccessDeniedException;
/**
* @Route("/profile/bookings", name="profile_bookings")
*/
public function bookings()
{
$user = $this->getUser();
if (!is_object($user) || !$user instanceof UserInterface) {
throw new AccessDeniedException('This user does not have access to this section.');
}
return $this->render('profile/bookings/bookings.html.twig', array(
'user' => $user,
));
}
}
答案 2 :(得分:1)
@Franck Gamess是正确的,但您也可以摆脱get
。
如果您写{{ user.firstName }}
,则树枝将自动将其关联到您的方法getFirstName()
。
我不知道为什么要使用snake_case编写属性,但是可以将其更改为camelCase并通过其“真实”名称访问属性。