Question

因此，我有一个查询来提取> 1的列的总和，然后按几个用户将某些部门分组，就像这样：

SELECT
   t.DEPARTMENT_ID
  ,SUM(CASE WHEN t.VALUE > 1 THEN 1 ELSE 0 END) AS Results

FROM TABLE t

WHERE t.USER_ID = 000
OR t.DEPARTMENT ID = 1001
   AND t.USER_ID IN
('01'
,'02'
)

OR t.DEPARTMENT_ID = 1002
   AND t.USER_ID IN
('02'
,'03'
)

GROUP BY t.DEPARTMENT ID

结果如下：

DEPARTMENT_ID    Results
1001             5
1002             7

现在，这行得通，因为在该列中指定了部门，而我只是对其进行分组。

但是，如果我想创建自己的团队（请参阅说明中的团队）并按团队负责人分组怎么办？例如：

SELECT
   t.DEPARTMENT_ID
  ,SUM(CASE WHEN t.VALUE > 1 THEN 1 ELSE 0 END) 

FROM TABLE t

WHERE t.USER_ID = 000   

--Team_1 
   OR t.DEPARTMENT ID = 1001
AND t.USER_ID IN
('01'
,'02'
)

OR t.DEPARTMENT_ID = 1002
   AND t.USER_ID IN
('02'
,'03'
)

-- Team_2
OR t.DEPARTMENT_ID = 1003
   AND t.USER_ID IN
('05'
,'06'
)

我希望结果显示如下：

TEAMS      RESULTS
Team_1     6
Team_2     4

我如何按团队分组？

Answer 1

使用CASE语句：

select case
       when t.DEPARTMENT_ID = 1001 and t.USER_ID in ('01', '02') then 'Team 1'
       when t.DEPARTMENT_ID = 1002 and t.USER_ID in ('02', '03') then 'Team 2'
       when t.DEPARTMENT_ID = 1003 and t.USER_ID in ('05', '06') then 'Team 3'
       end as Teams,
      sum(case when t.value > 1 then 1 else 0 end)
from TABLE t
group by 
      case when t.DEPARTMENT_ID = 1001 and t.USER_ID in ('01', '02') then 'Team 1'
           when t.DEPARTMENT_ID = 1002 and t.USER_ID in ('02', '03') then 'Team 2'
           when t.DEPARTMENT_ID = 1003 and t.USER_ID in ('05', '06') then 'Team 3'
      end

Answer 2

您可以建立VALUES()的列表并将其加入。比重复三遍要简单得多：

SELECT teams.name, SUM(CASE WHEN t.VALUE > 1 THEN 1 ELSE 0 END) AS Results
FROM (VALUES
    ('team 1', 1001, 1),
    ('team 1', 1001, 2),
    ('team 2', 1002, 3),
    ('team 2', 1002, 4),
    ('team 3', 1001, 5),
    ('team 3', 1001, 6)
) AS teams(name, deptid, userid)
INNER JOIN t ON teams.deptid = t.DEPARTMENT_ID AND teams.userid = t.USER_ID
GROUP BY teams.name

Answer 3

在select＆group by中使用案例表达式，并从select＆group by中删除department_ID。

SELECT CASE WHEN t.DEPARTMENT ID = 1001 AND t.USER_ID IN ('01','02') 
              OR t.DEPARTMENT_ID = 1002 AND t.USER_ID IN ('02','03') then 'Team1'
            WHEN t.DEPARTMENT_ID = 1003 AND t.USER_ID IN ('05','06') then 'Team2' END as Team
     , SUM(CASE WHEN t.VALUE > 1 THEN 1 ELSE 0 END)  as Results 
FROM TABLE t
WHERE t.USER_ID = 000   
--Team_1 
   OR (t.DEPARTMENT ID = 1001
  AND t.USER_ID IN ('01','02')
   OR t.DEPARTMENT_ID = 1002
  AND t.USER_ID IN ('02','03'))
-- Team_2
   OR (t.DEPARTMENT_ID = 1003
  AND t.USER_ID IN ('05','06'))
GROUP BY CASE WHEN t.DEPARTMENT ID = 1001 AND t.USER_ID IN ('01','02') 
                OR t.DEPARTMENT_ID = 1002 AND t.USER_ID IN ('02','03') then 'Team1'
              WHEN t.DEPARTMENT_ID = 1003 AND t.USER_ID IN ('05','06') then 'Team2' END

猜测（）可获得所需的结果。在基于团队评论的where子句中。

SQL-按筛选器分组

3 个答案: