我仅在工作电话以08开头时才尝试更新列

Question

UPDATE Contact
  SET MobilePhone = WorkPhone
    WHERE left(WorkPhone, 2) LIKE '%01%' 
      and MobilePhone = NULL and User = 992;

Answer 1

您可以尝试以下操作-您需要添加MobilePhone is NULL而不是MobilePhone = NULL

UPDATE Contact
  SET MobilePhone = WorkPhone
    WHERE left(WorkPhone, 2) LIKE '08%' 
      and MobilePhone is NULL and User = 992;

Answer 2

这是您想要的吗？

UPDATE Contact
    SET MobilePhone = WorkPhone
    WHERE WorkPhone LIKE '08%' AND  -- WorkPhone starts with "08"
          MobilePhone IS NULL AND    -- Probably your real problem
          User = 992;

仅将LIKE用于“开头为”。您的标题为“ 08”，因此使用了它。

您真正的问题可能是= NULL，因为它永远不会返回true，因此不会更新任何行。