显示某些天作为可能的交货日期

Question

我可能有订单的交货日期

$daysOff = ['Sat', 'Sun'];
for ($days = 1; $days <= 7; $days++) {
    $day = date("D", strtotime("today + $days day"));
    if (!in_array($day, $daysOff)) {
        $daysOnRearranged[] = date("D", strtotime("today + $days day"));
    }
}

这将显示未来5天的更正

  

周三，周四，周五，周一，周二

最后一天星期二显示的是今天（第4天），而不是第11天。我该如何解决？

Answer 1

这是应该做的。您的问题不合适，但已回答。

$daysOff = ['Sat', 'Sun'];

        for ($days = 1; $days <= 7; $days++) {
          $day = date("D", strtotime("today + $days day"));
          $date = date('d', strtotime("today + $days day"));
          if (!in_array($day, $daysOff)) {
            $daysOnRearranged[$date] = date("D", strtotime("today + $days day"));
          }
        }
print_r($daysOnRearranged);

Answer 2

您应该显示如下可用日期：

  $daysOff = ['Sat', 'Sun'];
    for ($days = 1; $days <= 7; $days++) {
        $day = date("D", strtotime("today + $days day"));
        if (!in_array($day, $daysOff)) {
            $daysOnRearranged[] = date("D, j M", strtotime("today + $days day"));
        }
    }

print_r($daysOnRearranged);