Question

我从外部API端点（例如Person API）获得了这样的数组，但是数组键名使用其他语言并且带有下划线-使用我的代码标准是不可接受的。该项目由Symfony 4.x和PHP 7.1运行

[
    'first_name_in_other_language' => 'value',
    'last_name_in_other_language' => 'value',
    ...more fields
]

但是我想将其转换为具有有效字段名称的类条目（例如：（Person不是教义实体-它是存储数据的简单对象）

class Person {private $firstName; private $lastName; ...more fields}

问题：我认为我应该制作某种映射器数组/对象，例如

['first_name_in_other_language' => 'firstName']

但是我找不到与Symfony相关的这种方法的任何示例也许是因为这个问题与水化器而不是与序列化器有关？

我从zend hydrator找到了这段代码there，它似乎支持我需要的功能（new MapNamingStrategy(['published' => 'isPublished'])）：

use Acme\Transaction;
use Zend\Hydrator\NamingStrategy\CompositeNamingStrategy;
use Zend\Hydrator\NamingStrategy\MapNamingStrategy;
use Zend\Hydrator\NamingStrategy\UnderscoreNamingStrategy;
use Zend\Hydrator\ObjectProperty as ObjectPropertyHydrator;

$underscoreNamingStrategy = new UnderscoreNamingStrategy();
$namingStrategy = new CompositeNamingStrategy([
    'isPublished' => new MapNamingStrategy(['published' => 'isPublished']),
    'publishedOn' => $underscoreNamingStrategy,
    'updatedOn'   => $underscoreNamingStrategy,
]);

$hydrator = new ObjectPropertyHydrator();
$hydrator->setNamingStrategy($namingStrategy);
$data = $hydrator->extract($transaction);

问题：可以使用Symfony序列化程序或其他Symfony组件对其进行存档吗？

Answer 1

如果我正确理解了您的问题，则可以为此类添加构造函数，如下所示：

class Person{
         private $firstName;
         private $lastName;
         //other stuff
         function __construct($your_api_answer){
            $this->firstName = $your_api_answer["first_name_key_of_answer"];
            $this->lastName = $your_api_answer["last_name_key_of_answer"];
            //initialize other stuff
         }
    }

$person = new Person($your_api_answer);

Answer 2

这是一个可行的示例。

<?php
    
    namespace MyCompany\Bundle\SymfonyCustomerBundle\Formatter;
    
    use Symfony\Component\Serializer\Serializer;
    use Symfony\Component\Serializer\Encoder\JsonEncoder;
    use Symfony\Component\Serializer\Normalizer\ObjectNormalizer;
    use Symfony\Component\Serializer\Mapping\Factory\ClassMetadataFactory;
    use Symfony\Component\Serializer\Mapping\Loader\AnnotationLoader;
    use Symfony\Component\Serializer\NameConverter\MetadataAwareNameConverter;
    use Doctrine\Common\Annotations\AnnotationReader;
    
    use Mycompany\Bundle\SymfonyCustomerBundle\Model\Contact;
    
    class ContactFormatter {
    
        public function __construct()
        {
            //TODO : Make it as a service injection for all formatter
            $classMetadataFactory = new ClassMetaDataFactory(
                new AnnotationLoader(new AnnotationReader())
            );
            $metadataAwareNameConverter = new MetadataAwareNameConverter($classMetadataFactory);
            $encoders = [new JsonEncoder()];
            $normalizers = [new ObjectNormalizer($classMetadataFactory, $metadataAwareNameConverter)];
    
            $this->serializer = new Serializer($normalizers, $encoders);
        }
    
        public function formatToModel(array $rawData): Contact
        {
            return $this->serializer->denormalize($rawData, Contact::class);
        }
    
        public function formatToArray(Contact $contact): array
        {   
            return $this->serializer->normalize($contact);
        }
    }

以及使用SerializedName批注的模型。

<?php

namespace Mycompany\Bundle\SymfonyCustomerBundle\Model;


use Symfony\Component\Validator\Constraints as Assert;
use Symfony\Component\Serializer\Annotation\SerializedName;

class Contact
{

    /**
     * @SerializedName("db_id_contact")
     */
    private int $idContact;

    /**
     * @SerializedName("db_nomContact")
     * @Assert\NotBlank
     */
    private ?string $lastName = null;
    
    /**
     * @SerializedName("db_prenomContact")
     * @Assert\NotBlank
     */
    private ?string $firstName = null;


    public function getIdContact(): int{
        return $this->idContact;
    }

    public function getLastName(): ?string {
        return $this->lastName;
    }

    public function getFirstName(): ?string {
        return $this->firstName;
    }

    public function setIdContact($value){
        $this->idContact = $value;
    }

    public function setLastName(?string $value){
        $this->lastName = $value;
    }

    public function setFirstName(?string $value){
        $this->firstName = $value;
    }
}

Symfony序列化器-数组到对象的转换-每个字段的命名策略

2 个答案: