Question

通过此查询，我遇到了错误

ERROR:  missing FROM-clause entry for table "inv"
LINE 1: update stock_picking set invoice_status = inv.date_invoice

我的目标是在满足所有条件的情况下将stock_picking post_date设置为inv.date_invoice，是否可以使用SQL？

update stock_picking set posting_date = inv.date_invoice
where id in 
(
SELECT DISTINCT sp.id
FROM stock_picking sp
                       INNER JOIN stock_move sm ON sp.id = sm.picking_id
                       INNER JOIN sale_order_line sol ON sm.sale_line_id = sol.id 
                       INNER JOIN sale_order so ON sol.order_id = so.id
                       INNER JOIN sale_order_invoice_rel so_inv_rel on so.id = so_inv_rel.order_id
                       INNER JOIN account_invoice inv on so_inv_rel.invoice_id = inv.id

    WHERE 

            sp.posting_date != inv.date_invoice
            and sm.posting_date != inv.date_invoice
            and sp.state = 'done'       
            and inv.state in ('open', 'paid')
            )

Answer 1

您可以在下面尝试

update stock_picking S set posting_date = A.date_invoice
from 
(
SELECT DISTINCT sp.id, inv.date_invoice
FROM stock_picking sp
                       INNER JOIN stock_move sm ON sp.id = sm.picking_id
                       INNER JOIN sale_order_line sol ON sm.sale_line_id = sol.id 
                       INNER JOIN sale_order so ON sol.order_id = so.id
                       INNER JOIN sale_order_invoice_rel so_inv_rel on so.id = so_inv_rel.order_id
                       INNER JOIN account_invoice inv on so_inv_rel.invoice_id = inv.id

    WHERE 

            sp.posting_date != inv.date_invoice
            and sm.posting_date != inv.date_invoice
            and sp.state = 'done'       
            and inv.state in ('open', 'paid')
            ) A where S.id=A.id

Answer 2

您需要一个UPDATE ... FROM才能从更新中的查询内部引用该列。稍后在WHERE子句中将它们连接。

UPDATE stock_picking u SET posting_date = t.date_invoice
FROM (
  SELECT DISTINCT ON (sp.id) 
    sp.id, inv.date_invoice
  FROM stock_picking sp
  INNER JOIN stock_move sm ON sp.id = sm.picking_id
  INNER JOIN sale_order_line sol ON sm.sale_line_id = sol.id 
  INNER JOIN sale_order so ON sol.order_id = so.id
  INNER JOIN sale_order_invoice_rel so_inv_rel on so.id = so_inv_rel.order_id
  INNER JOIN account_invoice inv on so_inv_rel.invoice_id = inv.id
  WHERE 
    sp.posting_date != inv.date_invoice
    and sm.posting_date != inv.date_invoice
    and sp.state = 'done'       
    and inv.state in ('open', 'paid')
  ORDER BY sp.id, inv.date_invoice DESC
) t
WHERE u.id = t.id

由于我不知道您的模型，所以我假设stock_picking和account_invoice之间的关系可能是1：N，因此使用DISTINCT ON将仅返回一个{{1} } date_invoice。您可以使用id + GROUP BY聚合函数来获得相同的结果。

请注意MAX/MIN和t表别名的使用。

Answer 3

由于更新查询正试图从u表中获取根本没有连接的数据，所以您会收到错误消息。

您也可以对更新查询进行联接。

inv

更新子句中缺少的记录

3 个答案: