在Java脚本中获取第一个数组中具有id的对象与其他数组中的id相同的对象

Question

我有2个对象数组。 他们是

array1 = [{
  id:2,
  name:"person2"
},{
  id:3,
  name:"person3"
},
{
  id:4,
  name:"person4"
},
{
  id:5,
  name:"person5"
},
];
array2 = [
{
    empId:2,
    isdeleted:false
},
{
    empId:4,
    isdeleted:false
}, 
{   
    empId:3,
    isdeleted:true
}];

我需要array1中的对象，其id与array2的empId匹配并且被删除为false。预先感谢。

Answer 1

您可以像这样使用filter和some：

let array1 = [{
    id: 2,
    name: "person2"
  }, {
    id: 3,
    name: "person3"
  },
  {
    id: 4,
    name: "person4"
  },
  {
    id: 5,
    name: "person5"
  },
];

let array2 = [{
    empId: 2,
    isdeleted: false
  },
  {
    empId: 4,
    isdeleted: false
  },
  {
    empId: 3,
    isdeleted: true
  }
];

let filteredArray = array1.filter(a => array2.some(b => b.empId === a.id && !b.isdeleted));
console.log(filteredArray);

Answer 2

尝试

let result = [];
array1.forEach(function(element1){
    array2.forEach(function(element2){
        if (element1.id === element2.empId && !element2.isdeleted){
            result.push(element);
        }
    });
});
console.log(result);

Answer 3

您可以尝试如下操作：

let array1 = [
    { id:2, name:"person2"},
    { id:3, name:"person3"},
    { id:4, name:"person4"},
    { id:5, name:"person5"}
];
  
let array2 = [
    { empId:2, isdeleted:false},
    { empId:4, isdeleted:false}, 
    { empId:3, isdeleted:true}
];

let result = array1.reduce((output, item) => {
    if (array2.find((item2) => !item2.isdeleted && item.id === item2.empId)) output.push(item);
    return output;
}, []);

console.log(result);

Answer 4

您可以将Array.filter()与find()一起在array2中查找具有该条件的对象：

var array1 = [{
    id: 2,
    name: "person2"
  }, {
    id: 3,
    name: "person3"
  },
  {
    id: 4,
    name: "person4"
  },
  {
    id: 5,
    name: "person5"
  },
];
var array2 = [{
    empId: 2,
    isdeleted: false
  },
  {
    empId: 4,
    isdeleted: false
  },
  {
    empId: 3,
    isdeleted: true
  }
];

var res = array1.filter((obj1)=>{
  var exist = array2.find((obj2)=> (obj1.id == obj2.empId && !obj2.isdeleted));
  return exist;
});
console.log(res);