Question

正在播放！框架1.5.1，为什么我要为something.Owner返回null？自动绑定不应该解决这个问题吗？

用户类别

    package models;

@Entity
@Table(name="objtest_user")
public class User extends Model
{
    @Required
    public String username;

    @Password
    @Required
    public String password;

    public String fullname;

    public User(String username, String password, String fullname)
    {
        this.username = username;
        this.password = password;
        this.fullname = fullname;
    }

    @Override
    public String toString()
    {
        return this.fullname;
    }
}

以及这个引用User类的Thingy类

    package models;

import java.util.*;
import javax.persistence.*;

import play.db.jpa.*;
import play.data.validation.*;

@Entity
public class Thingy extends Model
{
    @Required
    public String Name;

    @ManyToOne
    public User Owner;

    public Thingy(String name, User owner)
    {
        this.Name = name;
        this.Owner = owner;
    }

    @Override
    public String toString()
    {
        return Name;
    }
}

和此模板表格

#{extends 'main.html' /}
#{set title:'Home' /}

<p>Current user = ${currentUser}</p>


#{form @saveThingy(), id:'saveThingy'}
    <input type="text" id="thingy.Name" name="thingy.Name"/>
    <input type="hidden" id="thingy.Owner" name="thingy.Owner" value="${currentUser}"/>
    <input type="submit" id="Save" value="Save"/>
#{/form}

控制器方法

public static void saveThingy(Thingy thingy)
{
    System.out.println("Name = " + thingy.Name);
    System.out.println("Owner = " + thingy.Owner);

    thingy.save();
}

Answer 1

尝试更改以下行

<input type="hidden" id="thingy.Owner" name="thingy.Owner" value="${currentUser}"/>

收件人

<input type="hidden" id="thingy.Owner" name="thingy.Owner.id" value="${currentUser.id}"/>

如果您签出文档（https://www.playframework.com/documentation/1.2.x/controllers#params），并查找“ JPA对象绑定”部分，则说明要求子对象具有ID。找到对象的ID时播放，它将通过JPA / Hibernate加载相关的实体。

为什么我的嵌套POJO从Play表单中返回null！ 1.x

1 个答案: