我尝试将Python解释器嵌入C。 为了对此进行测试,我创建了一个共享库并 尝试使用ctypes在Python中加载此代码。不幸的是,这不是 工作,我想了解原因。
以下是示例c-代码:
#ifdef __cplusplus
extern "C" {
#endif
#include <Python.h>
int run_py(void);
int run_py2(void);
int
run_py(void)
{
printf("hello from run_py\n");
return 42;
}
int
run_py2(void)
{
printf("entering c-function: run_py()\n");
Py_Initialize();
PyRun_SimpleString("print('hello world')");
return 0;
}
#ifdef __cplusplus
}
#endif
因此,我使用gcc将其编译为“ mylib.so”,并使用python3.7-config --cflags和--ldflags进行链接等,以此类推。
这是我用来加载它的Python代码。
import ctypes as c
import os
import sys
if __name__ == '__main__':
print("running shared-lib integration test with python:\n{}".format(sys.version))
path = os.path.dirname(os.path.realpath(__file__))
dllfile = os.path.join(path, 'mylib.so')
dll = c.CDLL(str(dllfile))
print("loaded CDLL")
dll.run_py.restype = c.c_int
dll.run_py2.restype = c.c_int
print("now calling dll.run_py()...")
rv = dll.run_py()
print("called dll.run_py: rv={}".format(rv))
print("now calling dll.run_py2()...")
rv2 = dll.run_py2()
print("called dll.run_py2: rv={}".format(rv2))
因此,这仅加载了run_py和run_py2这两个函数 并执行它们。这是输出...
running shared-lib integration test with python:
3.7.1 (default, Oct 22 2018, 10:41:28)
[GCC 8.2.1 20180831]
loaded CDLL
now calling dll.run_py()...
hello from run_py
called dll.run_py: rv=42
now calling dll.run_py2()...
entering c-function: run_py()
Segmentation fault (core dumped)
因此,从根本上讲,这在调用run_py2时会导致段错误。
原因是调用PyRun_SimpleString
。
但是,如果我将其编译为独立的C程序
一切似乎都正常。我真的
想了解为什么会这样...但是目前我
提出想法,因此在此非常感谢您提供任何反馈。
BR jrsm
答案 0 :(得分:2)
我稍微更改了您的代码。另外,我正在测试 Win (因为这对我来说更方便),但是我确定 Nix 中的情况是相同的。
dll.c :
#include <stdio.h>
#include <Python.h>
#define PRINT_MSG_0() printf("From C - [%s] (%d) - [%s]\n", __FILE__, __LINE__, __FUNCTION__)
#if defined(_WIN32)
#define DLL_EXPORT_API __declspec(dllexport)
#else
#define DLL_EXPORT_API
#endif
#if defined(__cplusplus)
extern "C" {
#endif
DLL_EXPORT_API int test0(void);
DLL_EXPORT_API int test1(void);
#if defined(__cplusplus)
}
#endif
int test0(void) {
PRINT_MSG_0();
return 42;
}
int test1(void) {
PRINT_MSG_0();
Py_Initialize();
PRINT_MSG_0();
PyRun_SimpleString("print(\"Hello world!!!\")");
PRINT_MSG_0();
return 0;
}
code.py :
#!/usr/bin/env python3
import sys
from ctypes import CDLL,\
c_int
DLL = "./dll.so"
def main():
dll_dll = CDLL(DLL)
test0_func = dll_dll.test0
test0_func.argtypes = None
test0_func.restype = c_int
test1_func = dll_dll.test1
test1_func.argtypes = None
test1_func.restype = c_int
print("Calling {:}...".format(test0_func.__name__))
res = test0_func()
print("{:} returned {:d}".format(test0_func.__name__, res))
print("Calling {:}...".format(test1_func.__name__))
res = test1_func()
print("{:} returned {:d}".format(test1_func.__name__, res))
if __name__ == "__main__":
print("Python {:s} on {:s}\n".format(sys.version, sys.platform))
main()
输出:
(py35x64_test) e:\Work\Dev\StackOverflow\q053609932>"c:\Install\x86\Microsoft\Visual Studio Community\2015\vc\vcvarsall.bat" x64 (py35x64_test) e:\Work\Dev\StackOverflow\q053609932>dir /b code.py dll.c (py35x64_test) e:\Work\Dev\StackOverflow\q053609932>cl /nologo /DDLL /MD /Ic:\Install\x64\Python\Python\3.5\include dll.c /link /NOLOGO /DLL /OUT:dll.so /LIBPATH:c:\Install\x64\Python\Python\3.5\libs dll.c Creating library dll.lib and object dll.exp (py35x64_test) e:\Work\Dev\StackOverflow\q053609932>dir /b code.py dll.c dll.exp dll.lib dll.obj dll.so (py35x64_test) e:\Work\Dev\StackOverflow\q053609932>"e:\Work\Dev\VEnvs\py35x64_test\Scripts\python.exe" code.py Python 3.5.4 (v3.5.4:3f56838, Aug 8 2017, 02:17:05) [MSC v.1900 64 bit (AMD64)] on win32 Calling test0... From C - [dll.c] (26) - [test0] test0 returned 42 Calling test1... From C - [dll.c] (32) - [test1] From C - [dll.c] (34) - [test1] Traceback (most recent call last): File "code.py", line 30, in <module> main() File "code.py", line 24, in main res = test1_func() OSError: exception: access violation reading 0x0000000000000010
问题重现。首先,我认为是[Python 3]: void Py_Initialize()通话。但是后来我想起了[Python 3]: class ctypes.PyDLL(name, mode=DEFAULT_MODE, handle=None)(强调是我的),其中指出:
此类的实例的行为类似于CDLL实例,除了在函数调用期间 not 释放Python GIL,并且在函数执行后检查Python错误标志。如果设置了错误标志,则会引发Python异常。
因此,这仅对直接调用Python C api函数有用。
在 code.py 中用 PyDLL 替换 CDLL ,结果:
(py35x64_test) e:\Work\Dev\StackOverflow\q053609932>"e:\Work\Dev\VEnvs\py35x64_test\Scripts\python.exe" code.py Python 3.5.4 (v3.5.4:3f56838, Aug 8 2017, 02:17:05) [MSC v.1900 64 bit (AMD64)] on win32 Calling test0... From C - [dll.c] (26) - [test0] test0 returned 42 Calling test1... From C - [dll.c] (32) - [test1] From C - [dll.c] (34) - [test1] Hello world!!! From C - [dll.c] (36) - [test1] test1 returned 0