Question

我要突出显示页面上的文本，如果它与数组中的文本匹配。目的是突出显示页面上的重复项。

var iterator = document.evaluate('xpathgoeshere', document, null, XPathResult.UNORDERED_NODE_ITERATOR_TYPE, null);

try {
  var thisNode = iterator.iterateNext();
  var arrayList = [];

  while (thisNode) {
    arrayList.push(thisNode.textContent); 
    thisNode = iterator.iterateNext();
  }

  console.log(arrayList);

  for (var i = 0; i < arrayList.length; i++) {
    console.log(arrayList[i]);
  }   
} catch (e) {
  dump('Error: Document tree modified during iteration ' + e);
}

var arrayListDupes = arrayList.slice().sort();
var results = [];
for (var i = 0; i < arrayListDupes.length - 1; i++) {
    if (arrayListDupes[i + 1] == arrayListDupes[i]) {
    //while (results) {
        results.style.outline = "5px dashed red"; // I am probably doing
        results = iterator.iterateNext(); // it completely incorrect
        results.push(arrayListDupes[i]);
    }
}

console.log(results);

Answer 1

通过以下功能使用现有代码。

var TRange=null;

function findString (str) {
 if (parseInt(navigator.appVersion)<4) return;
 var strFound;
 if (window.find) {

  // CODE FOR BROWSERS THAT SUPPORT window.find

  strFound=self.find(str);
  if (!strFound) {
   strFound=self.find(str,0,1);
   while (self.find(str,0,1)) continue;
  }
 }
 else if (navigator.appName.indexOf("Microsoft")!=-1) {

  // EXPLORER-SPECIFIC CODE

  if (TRange!=null) {
   TRange.collapse(false);
   strFound=TRange.findText(str);
   if (strFound) TRange.select();
  }
  if (TRange==null || strFound==0) {
   TRange=self.document.body.createTextRange();
   strFound=TRange.findText(str);
   if (strFound) TRange.select();
  }
 }
 else if (navigator.appName=="Opera") {
  alert ("Opera browsers not supported, sorry...")
  return;
 }
 if (!strFound) alert ("String '"+str+"' not found!")
 return;
}

尝试像findString (results[0])一样呼叫，文本应在页面中突出显示。

findString()源和演示here

如果数组中存在匹配的文本，则在页面上突出显示文本

1 个答案: