Question

如何通过自定义FeatureAuthorize属性中的按位或运算传递多个参数，就像AttributeUsage支持AttributeTarget作为方法或类一样。

[AttributeUsage(AttributeTargets.Class | AttributeTargets.Method)]

下面是我要实现的示例，提供的任何功能（无论是汇款还是收款方法）都应该可以访问。

[FeatureAuthorize(Feature = EnumFeature.SendMoney | EnumFeature.ReceiveMoney)]
public ActionResult SendOrReceiveMoney(int? id, EnumBankAccountType? type)
{
 // My code
}

FeatureAuthorize属性的主体就像

。

[AttributeUsage(AttributeTargets.Class | AttributeTargets.Method)]
public class FeatureAuthorizeAttribute : AuthorizeAttribute
{
    public EnumFeature Feature { get; set; }

    public override void OnAuthorization(AuthorizationContext filterContext)
    {
        if (!IsFeatureAllowed(Feature)) // Verification in database.
        {
             // Redirection to not authorize page.
        }
    }
}

谢谢。

Answer 1

这样定义您的EnumFeature：

[Flags]
public enum EnumFeature {
  Send = 1,
  Received = 2,
  BalanceEnquery = 4,
  CloseAccount = 8
}

请注意，每个后续枚举值是下一个2的次幂。在auth属性中，可以使用Enum.HasFlag查看是否设置了标志。但是您可能要确保通过使用其他按位操作不会设置其他标志。

类似这样的东西

var acceptable = EnumFeature.Send | EnumFeature.Received;
var input = EnumFeature.Send | EnumFeature. CloseAccount;

// Negate the values which are acceptable, then we'll AND with the input; if that result is 0, then we didn't get any invalid flags set.  We can then use HasFlag to see if we got Send or Received
var clearAcceptable = ~acceptable;
Console.WriteLine($"Input valid: {(input & clearAcceptable) == 0}");

按位或作为自定义属性中的输入参数

1 个答案: