Question

我有以下xml（例如）

#!/bin/bash

set -e
shopt -s nullglob

for file in *.xml
do
  FILENAME=`xmlstarlet sel -t -m "/gameList/game" -v path $file`;
  echo "Appending $FILENAME into description on $file";
  xmlstarlet ed -L -s "/gameList/game" -t elem -n description -v "$FILENAME" $file;
done

好吧，我正在尝试执行sh脚本并在其上使用xmlstarlet。对于每个游戏节点，我想复制路径节点并将其插入到名为description的新节点中，如果description已经存在，则将其连接到那里的现有文本。

我真的对此很陌生，这是我到目前为止所做的。

<?xml version="1.0"?>
<gameList>
  <game>
    <path>./sunsetbl.zip</path>
    <name>sunsetbl</name>
    <playcount>8</playcount>
    <lastplayed>20180924T214132</lastplayed>
    <description>./sunsetbl.zip./ssriders.zip./kof97.zip./dino.zip./kof98n.zip</description>
  </game>
  <game>
    <path>./ssriders.zip</path>
    <name>Sunset Riders (4 Players ver EAC)</name>
    <playcount>4</playcount>
    <lastplayed>20181030T013801</lastplayed>
    <description>./sunsetbl.zip./ssriders.zip./kof97.zip./dino.zip./kof98n.zip</description>
  </game>
  <game>
    <path>./kof97.zip</path>
    <name>The King of Fighters '97 (NGM-2320)</name>
    <playcount>2</playcount>
    <lastplayed>20181030T035949</lastplayed>
    <description>./sunsetbl.zip./ssriders.zip./kof97.zip./dino.zip./kof98n.zip</description>
  </game>
  <game>
    <path>./dino.zip</path>
    <name>Cadillacs and Dinosaurs (World 930201)</name>
    <favorite>true</favorite>
    <playcount>26</playcount>
    <lastplayed>20181030T043441</lastplayed>
    <description>./sunsetbl.zip./ssriders.zip./kof97.zip./dino.zip./kof98n.zip</description>
  </game>
  <game>
    <path>./kof98n.zip</path>
    <name>kof98n</name>
    <playcount>1</playcount>
    <lastplayed>20181031T001024</lastplayed>
    <description>./sunsetbl.zip./ssriders.zip./kof97.zip./dino.zip./kof98n.zip</description>
  </game>
</gameList>

当然，结果很糟糕，所有路径值都在一行中并复制到每个游戏节点，这就是它的显示内容

Route::get('/user/avatar/{id?}', 'UserController@avatar');
Route::resource('user', 'UserController');

我很乐意为此提供任何帮助。

Answer 1

如果可以使用单独的XSLT文件，则解决方法如下。
使用此XSLT文件（此处称为app:layout_constraintTop_toBottomOf="@id/cardview_sendaudio_info"）：

trans.xslt

并使用以下脚本调用它：

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" />

    <xsl:template match="node()|@*">
        <xsl:copy>
            <xsl:apply-templates select="node()|@*" />
        </xsl:copy>
    </xsl:template>

    <!-- Add 'path' value to existing 'description' element -->
    <xsl:template match="description">    
      <xsl:copy>
        <xsl:value-of select="concat(.,../path)" />
      </xsl:copy>
    </xsl:template>

    <!-- Create new 'description' element -->
    <xsl:template match="game[not(description)]">  
      <xsl:copy>
        <xsl:copy-of select="node()|@*" />
        <description>
            <xsl:value-of select="path" />
        </description>
      </xsl:copy>
    </xsl:template>

</xsl:stylesheet>

这将创建扩展名为#!/bin/bash set -e shopt -s nullglob for file in *.xml do xmlstarlet tr trans.xslt "$file" > "$file.new.xml" done的新文件。

Xmlstarlet / Sh-将节点的内容复制到现有的新节点/ concat中

1 个答案: