Question

以下python代码在标识符中获取错误无效字符。知道为什么吗？我正在编写此函数未完成的函数，由于此错误导致它未运行，因此提早返回None。

def spotifyrecs(mylibrary, newsongs):
    total = 0
    count = 0
    genredict = {}
    for artist in mylibrary:
        artistsongs = mylibrary[artist]
        for adict in artistsongs:
            total += adict["plays"]
            count += 1
            if adict["genre"] not in genredict:
                genredict[adict["genre"]] = 1
            if adict["genre"] in genredict:
                genredict[adict["genre"]] += 1
    avgplays = round(total / count, 2)
    genrelist = []
    for genre in genredict:
        newtup = (genredict[genre], genre)
        genrelist.append(newtup)
    genrelist.sort(reverse = True)
    return None

library = {"Ariana Grande": [{"title": "thank u, next", "plays": 100, "genre": "pop"}, {"title": "Last Christmas", "plays": 44, "genre": "Christmas"}], "Khalid":[{"title": "Location", "plays": 15, "genre": "R&B"}, {"title": "Young, Dumb, and Broke", "plays": 90, "genre": "R&B"}]}
songs = [{"title": "Loving is Easy", "artist": "Rex Orange County", "plays": 115, "genre": "R&B"}, {"title": "Halo", "artist": "Beyonce", "plays": 9, "genre": "R&B"}, {"title": "Focus", "artist": "Ariana Grande", "plays": 112, "genre": "pop"}, {"title": "Winter", "artist": "Khalid", "plays": 800, "genre": "R&B"}]
print(spotifyrecs(library, songs))

错误：

  File "so.py", line 22
    library = {"Ariana Grande": [{"title": "thank u, next", "plays": 100, "genre": "pop"}, {"title": "Last Christmas", "plays": 44, "genre": "Christmas"}], "Khalid":[{"title": "Location", "plays": 15, "genre": "R&B"}, {"title": "Young, Dumb, and Broke", "plays": 90, "genre": "R&B"}]}
              ^
SyntaxError: invalid character in identifier

Answer 1

您的输入中包含一个非打印字符：除去<200b>字符，即可正常运行。

library = <200b>{
    "Ariana Grande": [
        {"title": "thank u, next", "plays": 100, "genre": "pop"}, 
        {"title": "Last Christmas", "plays": 44, "genre": "Christmas"}
    ],
    "Khalid":[
        {"title": "Location", "plays": 15, "genre": "R&B"},
        {"title": "Young, Dumb, and Broke", "plays": 90, "genre": "R&B"}
    ]}

请注意，这有助于很多使程序更具可读性。将其分成几行并进行缩进可以很好地完成两件事：（1）解析器为我提供了更好的位置，因为它可以在行尾发出错误消息；（2）通过这种方式，我可以更轻松地找到简单的错字和括号平衡。

标识符中的Python无效字符

1 个答案: