Question

在SQLite中，我的查询：

DELETE FROM notification_invoice t1 WHERE notificationDate >= 1536883200000  and providerId in ("1234","5678") 
    AND EXISTS (
         SELECT 1 FROM notification_invoice t2  WHERE 
         providerId in ("1234","5678") 
         and t2.notificationDate = t1.notificationDate          
         and t1.ownerKey = t2.ownerKey 
         AND t1._id < t2._id
    )

但是我得到了错误：

Error: [SQLITE_ERROR] SQL error or missing database (near "t1": syntax error)
SQLState:  null
ErrorCode: 1

Answer 1

在要删除的表上删除别名的使用将解决语法错误。

DELETE FROM notification_invoice
WHERE notificationDate >= 1536883200000
  AND providerId in ("1234","5678") 
  AND EXISTS (
         SELECT 1
           FROM notification_invoice t2
          WHERE t2.providerId in ("1234","5678") 
            AND t2.notificationDate = notification_invoice.notificationDate          
            AND t2.ownerKey         = notification_invoice.ownerKey 
            AND t2._id              > notification_invoice._id
    )

由于您没有描述要实现的数据或索引逻辑，因此无法说出逻辑是否正确。

也许子查询应该具有t2.providerId = notification_invoice.provider_id。在不知道数据，约束，预期逻辑等的情况下我们无法分辨。

Answer 2

Sqlite 确实支持带有DELETE的表别名，您使用的语法错误。您需要在表名和别名之间使用AS：

sqlite> CREATE TABLE foo(bar);
sqlite> INSERT INTO foo VALUES ('dog');
sqlite> SELECT * FROM foo;
bar       
----------
dog       
sqlite> DELETE FROM foo AS f WHERE f.bar = 'dog';
sqlite> SELECT * FROM foo;
sqlite>

如果您查看documentation for DELETE中的语法图，尤其是 qualified-table-name 语法图，您会发现AS不是可选的就像它在SELECT表名中一样。

Answer 3

DELETE语句在单个表上运行，不能使用表别名。别名导致您的错误。

有关类似情况，请参见stackoverflow.com/a/15832338/2577062。

SQLite：尝试使用别名删除时出现错误

3 个答案: