Question

我想要编写两个Linq表达式的结果。它们以

的形式存在

Expression<Func<T, bool>>

所以我要编写的两个本质上是一个参数（类型为T）的委托，它们都返回一个布尔值。我想要的结果是对布尔值的逻辑评价。我可能会将它作为扩展方法实现，所以我的语法类似于：

Expression<Func<User, bool>> expression1 = t => t.Name == "steve";
Expression<Func<User, bool>> expression2 = t => t.Age == 28;
Expression<Func<User, bool>> composedExpression = expression1.And(expression2);

稍后在我的代码中我想评估组合表达式

var user = new User();
bool evaluated = composedExpression.Compile().Invoke(user);

我已经探讨了一些不同的想法，但我担心它比我希望的更复杂。这是怎么做到的？

Answer 1

以下是一个例子：

var user1 = new User {Name = "steve", Age = 28};
var user2 = new User {Name = "foobar", Age = 28};

Expression<Func<User, bool>> expression1 = t => t.Name == "steve";
Expression<Func<User, bool>> expression2 = t => t.Age == 28;

var invokedExpression = Expression.Invoke(expression2, expression1.Parameters.Cast<Expression>());

var result = Expression.Lambda<Func<User, bool>>(Expression.And(expression1.Body, invokedExpression), expression1.Parameters);

Console.WriteLine(result.Compile().Invoke(user1)); // true
Console.WriteLine(result.Compile().Invoke(user2)); // false

您可以通过扩展方法重用此代码：

class User
{
  public string Name { get; set; }
  public int Age { get; set; }
}

public static class PredicateExtensions
{
  public static Expression<Func<T, bool>> And<T>(this Expression<Func<T, bool>> expression1,Expression<Func<T, bool>> expression2)
  {
    InvocationExpression invokedExpression = Expression.Invoke(expression2, expression1.Parameters.Cast<Expression>());

    return Expression.Lambda<Func<T, bool>>(Expression.And(expression1.Body, invokedExpression), expression1.Parameters);
  }
}

class Program
{
  static void Main(string[] args)
  {
    var user1 = new User {Name = "steve", Age = 28};
    var user2 = new User {Name = "foobar", Age = 28};

    Expression<Func<User, bool>> expression1 = t => t.Name == "steve";
    Expression<Func<User, bool>> expression2 = t => t.Age == 28;

    var result = expression1.And(expression2);

    Console.WriteLine(result.Compile().Invoke(user1));
    Console.WriteLine(result.Compile().Invoke(user2));
  }
}

Answer 2

您也可以使用LinqKit，它可以为您完成所有这些工作。请查看此链接 http://www.albahari.com/nutshell/linqkit.aspx

如何撰写现有的Linq表达式

2 个答案: