Question

我希望Id_Pass的两个或多个日期之间的差额超过10天。我已经尝试过datediff，但是我觉得它太复杂了。

+------------+-----------+-------+
|    Date    |  Id_Pass  | Value |
+------------+-----------+-------+
| 2011-03-18 | PASS00004 |    30 |
| 2011-03-19 | PASS00004 |    60 |
| 2012-02-25 | PASS00005 |    30 |
| 2012-04-25 | PASS00005 |    30 |
+------------+-----------+-------+

所需结果：

+-----------+
|  Id_Pass  |
+-----------+
| PASS00005 |
+-----------+

Answer 1

只需使用LAG窗口函数为每一行查找上一个日期：

SELECT Id_Pass
FROM (
    SELECT Id_Pass, Date, LAG(Date) OVER (PARTITION BY Id_Pass ORDER BY Date) AS PrevDate
    FROM yourdata
) AS cte
WHERE Date > DATEADD(DAY, 10, PrevDate)

Answer 2

您可以使用lag（）函数

select * from
(
select *, DATEDIFF(day, LAG(Date,1, Date) OVER (partition by Id_Pass ORDER BY Date)) as daydiff
)A where daydiff>10

多行之间的T-SQL日期差异

2 个答案: