Question

通过此SQL查询，我得到了以下结果：

SELECT Code,
 CASE
      WHEN MAX(running) = MIN(running) THEN MAX(running)
      ELSE MAX(running) - MIN(running)
 END
"RUNNING",
 date
FROM table
GROUP BY date;

结果：

Code    Running     Date
CC4       123       1/1/2018
CC4       12        1/11/2018
CC4       12000     4/2/2018
CC4       1000      4/10/2018

用户选择从日期（1/1/2018）到日期（4/10/2018）

“代码”列中的代码相同。我想在上面的查询中再次使用“最大和最小函数”，以仅实现“代码”列的一个结果

如何在oracle SQL中实现此目标？

Answer 1

I think you just want to GROUP BY code:

SELECT Code,
       (CASE WHEN MAX(running) = MIN(running) THEN MAX(running)
             ELSE MAX(running) - MIN(running)
        END) as "RUNNING"
FROM table
GROUP BY code;

如何在Oracle SQL中再次使用MAX和MIN函数获取值？

1 个答案: