我有一个包含7列的表格:
Start_hour | Start_minute | Start_second | End_hour | End_minute | end_second | date
我的任务是总结当天开始时间和结束时间之间的差异。我的查询已经做到了。可悲的是,我需要输出仅以分钟:秒为单位。例如,时间差的总和为2小时26分钟52秒。
我需要我的输出像这样:
126:52
我的查询现在看起来像这样:
SELECT
RIGHT(CONVERT(CHAR(8),
DATEADD(SECOND,
SUM(DATEDIFF(SECOND,
Timefromparts(start_hour, start_minute, start_second, 0, 0),
Timefromparts(end_hour, end_minute, end_second, 0, 0))
), 0), 108), 5)
FROM
opoznienia
WHERE
YEAR(data) = YEAR(GETDATE())
AND MONTH(data) = MONTH(GETDATE())
AND DAY(data) = DAY(GETDATE())
样本数据:
Start_hour | Start_minute | Start_second | End_hour | End_minute | end_second | date
10 15 0 10 30 30 2018-11-27 14:40:53.680
10 15 0 10 30 30 2018-11-30 10:16:20.610
6 10 30 6 23 45 2018-12-02 01:00:27.243
8 10 0 8 53 45 2018-12-02 14:42:48.663
10 5 13 10 55 23 2018-12-02 14:53:03.560
上面查询的输出:
47:13 (without RIGHT command it would be 01:47:13)
所需的输出:
107:13
答案 0 :(得分:0)
您需要计算秒数,然后根据需要对其进行格式化。根据秒数,您可以将分钟数除以60,剩下的就是秒数:
declare @NumberOfSeconds int = 7612
-- Returns 126:52
select concat(@NumberOfSeconds / 60, ':', FORMAT(@NumberOfSeconds % 60, 'D2'))
答案 1 :(得分:0)
这里是一种选择:
SELECT
numSeconds,
CASE WHEN numSeconds / 60 <= 100
THEN RIGHT('00' + CONVERT(VARCHAR(20), numSeconds / 60), 2)
ELSE CONVERT(VARCHAR(20), numSeconds / 60) END
+ ':' +
CASE WHEN numSeconds / 60 <= 100
THEN RIGHT('00' + CONVERT(VARCHAR(20), numSeconds % 60), 2)
ELSE CONVERT(VARCHAR(20), numSeconds % 60) END AS output
FROM yourTable;
代码中的丑陋与您期望分钟和秒组成部分至少要两位数字有关。因此,如果分钟或秒恰好是个位数,我们必须在每个成分上填充零。
答案 2 :(得分:0)
尝试以下
CREATE TABLE T(
StartHour INT,
StartMinute INT,
StartSecond INT,
EndHour INT,
EndMinute INT,
EndSecond INT,
[Date] DATE
);
INSERT INTO T VALUES
(10, 15, 0 , 10, 30, 30, '2018-11-27'),
(10, 15, 0 , 10, 30, 30, '2018-11-30'),
(6 , 10, 30, 6 , 23, 45, '2018-12-02'),
(8 , 10, 0 , 8 , 53, 45, '2018-12-02'),
(10, 5 , 13, 10, 55, 23, '2018-12-02');
SELECT *,
CAST( (DATEDIFF(Hour, StartTime, EndTime) * 60) +
(DATEDIFF(Minute, StartTime, EndTime) % 60) AS VARCHAR
) + ':' +
CAST(DATEDIFF(Second, StartTime, EndTime) % 60 AS VARCHAR)
FROM
(
SELECT [Date],
TIMEFROMPARTS(StartHour, StartMinute, StartSecond, 0, 0) StartTime,
TIMEFROMPARTS(EndHour, EndMinute, EndSecond, 0, 0) EndTime
FROM T
) TT
如果需要,您也可以SUM()
和GROUP BY [Date]
。
SELECT [Date],
CAST( SUM( (DATEDIFF(Hour, StartTime, EndTime) * 60) +
(DATEDIFF(Minute, StartTime, EndTime) % 60)
) AS VARCHAR
) + ':' +
CAST(SUM(DATEDIFF(Second, StartTime, EndTime) % 60) AS VARCHAR)
FROM
(
SELECT [Date],
TIMEFROMPARTS(StartHour, StartMinute, StartSecond, 0, 0) StartTime,
TIMEFROMPARTS(EndHour, EndMinute, EndSecond, 0, 0) EndTime
FROM T
) TT
GROUP BY [Date]
更新
似乎您正在寻找
SELECT [Date],
CAST(SUM(DATEDIFF(Second, StartTime, EndTime)) / 60 AS VARCHAR) + ':' +
CAST(SUM(DATEDIFF(Second, StartTime, EndTime)) % 60 AS VARCHAR) [MM:SS]
FROM
(
SELECT [Date],
TIMEFROMPARTS(StartHour, StartMinute, StartSecond, 0, 0) StartTime,
TIMEFROMPARTS(EndHour, EndMinute, EndSecond, 0, 0) EndTime
FROM T
) TT
GROUP BY [Date];
返回:
+---------------------+--------+
| Date | MM:SS |
+---------------------+--------+
| 27/11/2018 00:00:00 | 15:30 |
| 30/11/2018 00:00:00 | 15:30 |
| 02/12/2018 00:00:00 | 107:10 |
+---------------------+--------+
答案 3 :(得分:0)
其他答案更好,但是要了解您尝试执行的操作中可能缺少的内容,可以查看使用DatePart的位置。 ->“
..(如果没有RIGHT命令,它将是01:47:13)
“这是您需要使用零件而不是整个零件的线索...
SELECT Cast
(
Datepart
(
hour,
DATEADD(second,sum(datediff(second,
TIMEFROMPARTS ( Start_hour, Start_minute, Start_second, 0, 0),
TIMEFROMPARTS ( End_hour, End_minute, End_second, 0, 0))),0)
) * 60
+
Datepart
(
minute,
DATEADD(second,sum(datediff(second,
TIMEFROMPARTS ( Start_hour, Start_minute, Start_second, 0, 0),
TIMEFROMPARTS ( End_hour, End_minute, End_second, 0, 0))),0)
) As varchar)
+
':'
+
Cast
(
Datepart
(
second,
DATEADD(second,sum(datediff(second,
TIMEFROMPARTS ( Start_hour, Start_minute, Start_second, 0, 0),
TIMEFROMPARTS ( End_hour, End_minute, End_second, 0, 0))),0)
) As varchar) as result
from minsec