Question

我看到了一系列与我的问题类似但又不太相同的问题，以某种方式，我必须更改当前在DB上存储文件的方式。

我在第一个文件（getPic.php）上有一个表格：

<form enctype="multipart/form-data" method="POST" action="sendPics.php">
        <font size=4 color=DarkBlue><b>Choose 5 photos of your pet:</b></font><br><br>
    <input type="file" name="file[]" multiple="multiple" /><br><br>
    <input name="send" type="submit" value="Upload photos">

另一个（sendPics.php）

$directory = "Images/";

if(!is_dir($directory)){ 
    echo "Folder does not exist";
}else{
    $file = isset($_FILES['file']) ? $_FILES['file'] : FALSE;
    for ($control = 0; $control < count($file['name']); $control++){

        $destiny = $directory."/".$file['name'][$control];
        if(move_uploaded_file($file['tmp_name'][$control], $destiny)){
            echo "Upload successful<br>"; 
        }else{
            echo "Error uploading the file";
        }   
    }
}

$destiny = "/".$destiny;

我在MySQL中的表如下：

Field           | Type       
----------------+------------
 idPetsPics     | int(11)    
 linkProfilePic | varchar(60)
 linkPhoto1     | varchar(60)
 linkPhoto2     | varchar(60)
 linkPhoto3     | varchar(60)
 linkPhoto4     | varchar(60)
 Pet_idPet      | int(11)      //(FK with PetsID on Pet's table)

所以我需要存储上传照片的路径。目前，我只能将第一个存储在DB上，尽管所有5张照片都已成功到达目标文件夹。现在我有：

$petID = $_SESSION['petID']; // obtained from a third file (queries to insert date into Pet)
require_once('dbConnection.php');


$insertPetPic = "INSERT INTO petPic (idPetsPics, linkProfilePic, Pet_idPet) VALUES (NULL, '$destiny', $petID[0])";
mysqli_query($conn, $insertFotoPet);

如何更改代码以存储所有5条路径？

Answer 1

对于成功移动的每个图像，您需要将图像的路径存储在某个地方，例如存储在$paths数组中：

$directory = "Images/";
$paths = array();

if(!is_dir($directory)){ 
    echo "Folder does not exist";
}else{
    $file = isset($_FILES['file']) ? $_FILES['file'] : FALSE;
    for ($control = 0; $control < count($file['name']); $control++){

        $destiny = $directory."/".$file['name'][$control];
        if(move_uploaded_file($file['tmp_name'][$control], $destiny)){
            $paths[] = $destiny;
            echo "Upload successful<br>"; 
        }else{
            echo "Error uploading the file";
        }   
    }
}

然后在查询中使用数组中的路径：

$insertPetPic = "INSERT INTO petPic (idPetsPics, linkProfilePic, linkPhoto1, linkPhoto2, linkPhoto3, linkPhoto4, Pet_idPet) VALUES (NULL, '$paths[0]', '$paths[1]', '$paths[2]', '$paths[3]', '$paths[4]', $petID[0])";

在MySQL DB上按目标文件夹存储多个上传

1 个答案: