Question

这是我在CategoryController.php中的代码

public function addCategory(Request $request){
    if($request->isMethod('post')){
        $data = $request->all();
      //  echo "<pre>", print_r($data);die;
        $category = new Category;//in the http
        $category->name = $data['category_name'];
        $category->description = $data['description'];
        $category->url = $data['url'];
        $category->save();
    }
    else{

    }
    return view('admin.categories.add_category');
  }
}

我在数据库中的表名是categories

Answer 1

第1步：数据库连接。

https://laravel.com/docs/5.7/database

Laravel在幕后自动设置连接。您的config / database.php文件包含数据库凭据和主机（此处的实际值通常存储在应用程序根目录中的.env文件中）。 Laravel将启动，获取那些database.php配置值并连接到数据库

第2步：雄辩的ORM

https://laravel.com/docs/5.7/eloquent

Laravel结合了Eloquent ORM，用于抽象化与数据库的通信。数据库中的每个表都可以绑定到一个类，该类被雄辩地称为Model。这就是Category.php类文件的外观：

namespace App\Models;

use Illuminate\Database\Eloquent\Model;

class Category extends Model
{
    // This variable tells eloquent which table this model is trying to access.
    protected $table = 'categories';
}

然后在CategoryController中创建一个新模型。

// Create a new model instance - this is like creating a new row in an SQL editor.
$category = new Category;

// Here, you set the field values of the row.
// Each of the attributes below corresponds to a column name in the table.
// Right now this data is not in the database.
$category->name = $data['category_name'];
$category->description = $data['description'];
$category->url = $data['url'];

// And here we call the save() method, to actually execute the insert command.
// This is going to construct a query behind the scenes, and using the database
// connection set in configuration file, send it to the server and execute it.
$category->save();

// And here, a new row is already inserted in the database and you can access
// all of it's values.
var_dump($category->id);

我建议您阅读Laravel文档-的确写得很好并且易于理解，可以在Google中搜索很多这些基础知识，并且那里有很多信息。

我需要有关此代码如何将数据插入到数据库中的表中的说明（Laravel）

1 个答案: