Question

Output Should be:

Please enter employee's id: 1
Please enter your full name: Jane Doe
Please enter employee's salary: 98500.9718
Employee 1 is set successfully

Please enter employee's id: 2
Please enter your full name: John Doe
Please enter employee's salary: 96500.8723
Employee 2 is set successfully

Employee 1
Name - Jane Doe
Salary - 98500.97

Employee 2
Name - John Doe
Salary - 96500.87`

我的代码：

#include <stdio.h>
#include <string.h>
#define SIZE 2

struct Employee
{
int id;
char fullName[32];
double salary;
};

void setEmployee(struct Employee *);
void getFullName(char *);
void getId(int *);
void setSalary(double *);
void printEmployee(const struct Employee *);
void flushKeyboard()
{
    while (getchar() != '\n');
}

int main(void)
{
    struct Employee Employees[SIZE];
    int i = 0;
    for (i = 0;i < SIZE;i++)
    {
    setEmployee(Employees);
}
for (i = 0;i < SIZE;i++) {
    printEmployee(Employees);
}

return 0;
}
void setEmployee(struct Employee *employee1)
{
    getId(&employee1->id);
    getFullName(&employee1->fullName);
    setSalary(&employee1->salary);
    printf("Employee %d is set successfully\n\n", (employee1->id));

}
void getFullName(char *name1)
{
    printf("Please enter your full name: ");
    scanf(" %31[^\n]", name1);
flushKeyboard();

}
void getId(int *identity)
{
    printf("Please enter employee's id: ");
    scanf("%d", &identity);

}
void setSalary(double *salary)
{
    printf("Please enter employee's salary: ");
    scanf("%lf", salary);

}
void printEmployee(const struct Employee *final)
{
        printf("Employee: %d\n", final->id);
        printf("Name: %s\n", final->fullName);
        printf("Salary: %.2lf\n\n", final->salary);
}

运行完整个代码后，我的输出仅显示用户在第二个for循环中输入的值。因此，值将相同。员工编号，姓名和薪水将相同，而不是给我2个用户输入的单独值。我的问题是，为什么它继续给我同样的价值？我会使用for循环，但是由于某些原因我不允许使用for循环。

Answer 1

$card_query = "INSERT INTO CreditCard (Customer_ID, CreditCard_Number, CreditCard_Expiration_Date, CreditCard_Type, CreditCard_CVV_Code)
 VALUES(?,?,?,?,?);";

在这里您忘记了使用计数变量->

$card_query = "INSERT INTO CreditCard (Customer_ID, CreditCard_Number, CreditCard_Expiration_Date, CreditCard_Type, CreditCard_CVV_Code)
 VALUES(?,?,?,?,?)";

当您像这样传递整个数组时，会发生以下情况：将数组decayes to a pointer传递到数组中的第一个元素，这对函数很合适，因为它需要指向$card_query = "INSERT INTO CreditCard ( Customer_ID, CreditCard_Number, CreditCard_Expiration_Date, CreditCard_Type, CreditCard_CVV_Code ) VALUES(?,?,?,?,?)"; $card_result = $conn->prepare($card_query); $card_result->bind_param("isssi", $cust_ID, $card_num, $exp_date, $card_type, $cvv); $card_result->execute(); if($card_result->affected_rows === 0){ print( "<p>Could not save card information!</p>" ); die( mysql_error() . "</body></html>" ); }结构的指针。但随后，它仅打印阵列中的第一个员工。

如何使用结构在C程序中打印此输出？

1 个答案: