如何在熊猫中拆分groupby函数生成的元组

Question

我的代码

data = pd.read_csv('input_file', header = None, delimiter="\t", names = ['chr', 'sTSS', 'eTSS', 'gene', 'clust1', 'clust2'])

dup_clust2 = data.groupby('clust2').filter(lambda x: len(x) > 1)

for element in dup_clust2.groupby('clust2'):
    print(element)

输入：

chr2   166760255  166760255  Cse1l_tss10   52        5426
chr2   166760282  166760282  Cse1l_tss9    52        5426
chr2   166885599  166886548  IRF8          150.18    5431
chr2   166885925  166885925  Znfx1_tss1    52        5433

输出：

(5426,    chr    sTSS    eTSS    gene    clust1    clust2
0    chr2    166760255    166760255    Cse1l_tss10    52.0    5426
1    chr2    166760282    166760282    Cse1l_tss9    52.0    5426)

必需的输出：两行分割成元组

(0    chr2    166760255    166760255    Cse1l_tss10    52.0    5426)
(1    chr2    166760282    166760282    Cse1l_tss9     52.0    5426)