我想使用DTO与Angular通信,但实际上它不起作用。我想创建POST请求,以使用Dto模型将数据从应用程序添加到数据库中。
我的班级客户:
@Entity
@Table(name = "customer")
public class Customer {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private int id;
@Column(name = "name")
private String name;
@OneToMany
private List<Ticket> ticket;
...
CustomerDto类:
public class CustomerDto {
private String name;
private List<TicketDto> ticket;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public List<TicketDto> getTicket() {
return ticket;
}
public void setTicket(List<TicketDto> ticket) {
this.ticket = ticket;
}
}
CustomerController类:
@Autowired
CustomerService customerService;
@PostMapping(value = "/customers/create")
public Customer postCustomer(@RequestBody CustomerDto customerDto, List<TicketDto> ticketDtos) {
//ArrayList<TicketDto> tickets = new ArrayList<>();
ticketDtos.add(customerDto.getName());
ticketDtos.add(customerDto.getTicket());
Customer _customer = customerService.save(new Customer(customerDto.getName(), ticketDtos ));
return _customer;
}
CustomerService:
public interface CustomerService {
void save(CustomerDto customerDto, List<TicketDto> ticketDtos);
}
CustomerServiceImpl:
@Service
public class CustomerServiceImpl implements CustomerService {
@Autowired
CustomerRepository repository;
@Override
public void save(CustomerDto customerDto, List<TicketDto> ticketDtos) {
Customer customer = new Customer();
customer.setName(customerDto.getName());
customer.setTicket(customerDto.getTicket());
List<Ticket> tickets = new ArrayList<>();
for (TicketDto ticketDto : ticketDtos) {
Ticket ticket = new Ticket();
ticket.setDestinationCity(ticketDto.getDepartureCity());
ticket.setDestinationCity(ticketDto.getDestinationCity());
tickets.add(ticket);
}
}
答案 0 :(得分:1)
由于CustomerServiceImpl接受了CustomerDto和TicketDtos列表,因此您需要如下更改控制器上的方法调用:
CustomerController类:
@Autowired
CustomerService customerService;
@PostMapping(value = "/customers/create")
public Customer postCustomer(@RequestBody CustomerDto customerDto) {
Customer _customer = customerService.save(customerDto));
return _customer;
}
并将CustomerServiceImpl更新为:
@Service
public class CustomerServiceImpl implements CustomerService {
@Autowired
CustomerRepository repository;
// change save to return saved customer
@Override
public Customer save(CustomerDto customerDto) {
Customer customer = new Customer();
customer.setName(customerDto.getName());
// customer.setTicket(customerDto.getTicket()); // remove this
List<Ticket> tickets = new ArrayList<>();
for (TicketDto ticketDto : customerDto.getTicketDtos) {
Ticket ticket = new Ticket();
ticket.setDestinationCity(ticketDto.getDepartureCity());
ticket.setDestinationCity(ticketDto.getDestinationCity());
tickets.add(ticket);
}
customer.setTickets(tickets); // add this to set tickets on customer
return repository.save(customer);
}
显然,您还需要更改界面:
public interface CustomerService {
Customer save(CustomerDto customerDto);
}
答案 1 :(得分:0)
对于实体-DTO 转换,我们需要使用ModelMapper 或mapstruct 库。 借助这些库,我们可以轻松地从 Dto 转换为实体,将实体转换为 dto 对象。添加任何依赖后,我们就可以使用它了。
我们如何使用,让我们看看...
在 spring 配置中定义 modelMapper bean。
@Bean
public ModelMapper modelMapper() {
return new ModelMapper();
}
假设我们需要将 List 转换为 List obj 那么我们可以简单地执行:
List<TicketDto> ticketDtos = .... //Suppose It is holding some data
List<Ticket> tickets = ticketDtos.stream()
.map(tkt-> mappper.map(tkt, ticket.class))
.collect(Collectors.toList());
使用起来非常简单,比如mappper.map(targetClass, DestinationClass.class) 我在这里使用了 Java8 代码,但您可以使用任何人。希望对你有帮助。