Django 2.1.3错误:__init __()接受1个位置参数,但给出了2个

时间:2018-12-01 15:24:49

标签: python django django-models django-views

我正在尝试使用Django 2.1.3和python 3.7.1开发一个网站 当我转到主页时,出现此错误:

在/ __init __()处的

TypeError接受1个位置参数,但给出了2个位置

以下是有关我编写的代码的一些详细信息:

回退

Environment:


Request Method: GET
Request URL: http://127.0.0.1:8000/

Django Version: 2.1.3
Python Version: 3.7.1
Installed Applications:
['django.contrib.admin',
 'django.contrib.auth',
 'django.contrib.contenttypes',
 'django.contrib.sessions',
 'django.contrib.messages',
 'django.contrib.staticfiles',
 'core',
 'crispy_forms']
Installed Middleware:
['django.middleware.security.SecurityMiddleware',
 'django.contrib.sessions.middleware.SessionMiddleware',
 'django.middleware.common.CommonMiddleware',
 'django.middleware.csrf.CsrfViewMiddleware',
 'django.contrib.auth.middleware.AuthenticationMiddleware',
 'django.contrib.messages.middleware.MessageMiddleware',
 'django.middleware.clickjacking.XFrameOptionsMiddleware']



Traceback:

File "C:\Users\andre\AppData\Local\Programs\Python\Python37-32\lib\site-packages\django\core\handlers\exception.py" in inner
  34.             response = get_response(request)

File "C:\Users\andre\AppData\Local\Programs\Python\Python37-32\lib\site-packages\django\core\handlers\base.py" in _get_response
  126.                 response = self.process_exception_by_middleware(e, request)

File "C:\Users\andre\AppData\Local\Programs\Python\Python37-32\lib\site-packages\django\core\handlers\base.py" in _get_response
  124.                 response = wrapped_callback(request, *callback_args, **callback_kwargs)

File "C:\Users\andre\AppData\Local\Programs\Python\Python37-32\lib\site-packages\django\contrib\auth\decorators.py" in _wrapped_view
  21.                 return view_func(request, *args, **kwargs)

Exception Type: TypeError at /
Exception Value: __init__() takes 1 positional argument but 2 were given

core / models.py

这只是数据库上的一个表:

from django.db import models


class Evento(models.Model):
    titolo_evento = models.CharField(max_length=30)
    data_inizio = models.DateTimeField()
    data_fine = models.DateTimeField()

    def __str__(self):
        return self.titolo_evento

    class Meta:
        verbose_name = 'Evento'
        verbose_name_plural = 'Eventi'

core / views.py

在这里,我只想在用户通过身份验证后才能在主页上看到数据库“ Eventi”,我认为错误在这里,但是我不知道在哪里:

from django.contrib.auth.decorators import login_required
from .models import Evento
from django.views.generic.list import ListView


@login_required
class HomeView(ListView):
    queryset = Evento.objects.all()
    template_name = 'core/homepage.html'
    context_object_name = 'lista_eventi'

core / urls.py

from django.urls import path
from . import views


urlpatterns = [
    path('', views.HomeView, name='homepage'),
    ]

urls.py(项目)

  from django.contrib import admin
    from django.urls import path, include

    urlpatterns = [
        path('admin/', admin.site.urls),
        path('', include('core.urls')),
        path('accounts/', include('django.contrib.auth.urls'))
    ]

2 个答案:

答案 0 :(得分:5)

在URL中声明时,您需要在基于类的视图的末尾使用as_view()

path('', views.HomeView.as_view(), name='homepage'),

此外,在使用login_required装饰器时,需要在CBV的分派方法上使用它:

from django.contrib.auth.decorators import login_required
from django.utils.decorators import method_decorator

class HomeView(ListView):

    @method_decorator(login_required)
    def dispatch(self, *args, **kwargs):
        return super(HomeView, self).dispatch(*args, **kwargs)

答案 1 :(得分:0)

在 `urls.py 中替换为这个路径代码:

path(' ', views.HomeView.as_view(), name='homepage'),

from django.urls import path
from . import views
 
urlpatterns = [
     path(' ', views.HomeView.as_view(), name='homepage'),
]