Question

我有一个带有无限节点的树结构，如何将Togglable content放在每个节点下？我的意思是Togglable content对于所有节点都是相同的。我为min-width设置了min-height和.tree li a，并且希望Togglable content在.tree li a以下。
现在切换1个节点的工作，而该工作不在每个节点下。
照片：

    var toggle = document.getElementById("toggle");
    var content = document.getElementById("content");

    toggle.addEventListener("click", function () {
      content.classList.toggle("appear");
    }, false);

  body {
      font-family: sans-serif;
      font-size: 15px;
    }

    .tree {
      transform: rotate(0deg);
      transform-origin: 50%;
    }

    .tree ul {
      position: relative;
      padding: 1em 0;
      white-space: nowrap;
      margin: 0 auto;
      text-align: center;
    }

    .tree ul::after {
      content: '';
      display: table;
      clear: both;
    }

    .tree li {
      display: inline-block;
      vertical-align: top;
      text-align: center;
      list-style-type: none;
      position: relative;
      padding: 1em 0.5em 0 0.5em;
    }

    .tree li::before,
    .tree li::after {
      content: '';
      position: absolute;
      top: 0;
      right: 50%;
      border-top: 1px solid #ccc;
      width: 50%;
      height: 1em;
    }

    .tree li::after {
      right: auto;
      left: 50%;
      border-left: 1px solid #ccc;
    }

    .tree li:only-child::after,
    .tree li:only-child::before {
      display: none;
    }

    .tree li:only-child {
      padding-top: 0;
    }

    .tree li:first-child::before,
    .tree li:last-child::after {
      border: 0 none;
    }

    .tree li:last-child::before {
      border-right: 1px solid #ccc;
      border-radius: 0 5px 0 0;
    }

    .tree li:first-child::after {
      border-radius: 5px 0 0 0;
    }

    .tree ul ul::before {
      content: '';
      position: absolute;
      top: 0;
      left: 50%;
      border-left: 1px solid #ccc;
      width: 0;
      height: 1em;
    }

    .tree li a {
      min-width: 16em;
      min-height: 5em;
      border: 1px solid #ccc;
      padding: 0.5em 0.75em;
      text-decoration: none;
      display: inline-block;
      border-radius: 5px;
      color: #333;
      position: relative;
      top: 1px;
      transform: rotate(0deg);
    }

    .tree li a:hover,
    .tree li a:hover+ul li a {
      background: #e9453f;
      color: #fff;
      border: 1px solid #e9453f;
    }

    .tree li a:hover+ul li::after,
    .tree li a:hover+ul li::before,
    .tree li a:hover+ul::before,
    .tree li a:hover+ul ul::before {
      border-color: #e9453f;
    }

    #content {
      /* DON'T USE DISPLAY NONE/BLOCK! Instead: */
      background: #cf5;
      padding: 10px;
      position: inherit;
      visibility: hidden;
      opacity: 0.4;
      transition: 0.6s;
      -webkit-transition: 0.6s;
      transform: translateY(-20%);
      -webkit-transform: translateY(-20%);
    }

    #content.appear {
      visibility: visible;
      opacity: 1;
      transform: translateX(0);
      -webkit-transform: translateX(0);
    }

<body>
  <div class="row">
    <div class="col-sm-12 text-center tree">
      <ul>
        <li id="toggle">
          <a href="#">parent</a>
          <ul>
            <li id="toggle">
              <a href="#">boy</a>
            </li>
            <li id="toggle">
              <a href="#">girl</a>
            </li>
          </ul>
        </li>
      </ul>

      <div id="content">This Togglable content is same for all id="toggle"</div>

    </div>
  </div>

  
</body>

Answer 1

请勿对多个元素使用相同的id，id应该始终是唯一的。

改为使用class。

<li class="toggle"> ... </li>

然后，您可以在JavaScript中创建对象数组来访问这些元素：

let toggle_list = document.querySelectorAll(".toggle");

然后，您可以使用for循环（或者，如果想要的话，可以使用forEach方法）为每个事件分配一个事件侦听器：

for(let i = 0; i < toggle_list.length; i++) {
  toggle_list[i].addEventListener("click", toggleClick);
}

现在，您可以定义如下的toggleClick函数：

function toggleClick(e) {
  e.target.children[0].classList.toggle("appear");
}

在此示例中，children[0]将定位被单击的<li>中的第一个元素，并且该子元素不需要单独的class="content"属性。如果不是您想要的，则可以将其更改为其他内容（也许children[1]：D）。

更多信息：https://developer.mozilla.org/en-US/docs/Web/API/Document/querySelectorAll

Answer 2

据我所知id属性对于html文档应该是唯一的

您可以尝试使用data-属性，然后例如通过data-toggle匹配元素

link for documentation

Answer 3

✔️通过这种方式解决了

  function toggleDocs(event) {
var next = event.target.nextElementSibling;
if (next.style.display == "none") {
  next.style.display = "block";

} else {
  next.style.display = "none";
}
  }
  document.addEventListener('click', toggleDocs, true);

  body {
      font-family: sans-serif;
      font-size: 15px;
    }

    .tree {
      transform: rotate(0deg);
      transform-origin: 50%;
    }

    .tree ul {
      position: relative;
      padding: 1em 0;
      white-space: nowrap;
      margin: 0 auto;
      text-align: center;
    }

    .tree ul::after {
      content: '';
      display: table;
      clear: both;
    }

    .tree li {
      display: inline-block;
      vertical-align: top;
      text-align: center;
      list-style-type: none;
      position: relative;
      padding: 1em 0.5em 0 0.5em;
    }

    .tree li::before,
    .tree li::after {
      content: '';
      position: absolute;
      top: 0;
      right: 50%;
      border-top: 1px solid #ccc;
      width: 50%;
      height: 1em;
    }

    .tree li::after {
      right: auto;
      left: 50%;
      border-left: 1px solid #ccc;
    }

    .tree li:only-child::after,
    .tree li:only-child::before {
      display: none;
    }

    .tree li:only-child {
      padding-top: 0;
    }

    .tree li:first-child::before,
    .tree li:last-child::after {
      border: 0 none;
    }

    .tree li:last-child::before {
      border-right: 1px solid #ccc;
      border-radius: 0 5px 0 0;
    }

    .tree li:first-child::after {
      border-radius: 5px 0 0 0;
    }

    .tree ul ul::before {
      content: '';
      position: absolute;
      top: 0;
      left: 50%;
      border-left: 1px solid #ccc;
      width: 0;
      height: 1em;
    }

    .tree li a {
      min-width: 16em;
      min-height: 5em;
      border: 1px solid #ccc;
      padding: 0.5em 0.75em;
      text-decoration: none;
      display: inline-block;
      border-radius: 5px;
      color: #333;
      position: relative;
      top: 1px;
      transform: rotate(0deg);
    }

    .tree li a:hover,
    .tree li a:hover+ul li a {
      background: #e9453f;
      color: #fff;
      border: 1px solid #e9453f;
    }

    .tree li a:hover+ul li::after,
    .tree li a:hover+ul li::before,
    .tree li a:hover+ul::before,
    .tree li a:hover+ul ul::before {
      border-color: #e9453f;
    }

    #content {
      /* DON'T USE DISPLAY NONE/BLOCK! Instead: */
      background: #cf5;
      padding: 10px;
      position: inherit;
      visibility: hidden;
      opacity: 0.4;
      transition: 0.6s;
      -webkit-transition: 0.6s;
      transform: translateY(-20%);
      -webkit-transform: translateY(-20%);
    }

    #content.appear {
      visibility: visible;
      opacity: 1;
      transform: translateX(0);
      -webkit-transform: translateX(0);
    }

<body>
  <div class="row">
<div class="col-sm-12 text-center tree">
  <ul>
    <li class="clickable-heading">
      <a href="#">parent</a>
      <div style="display:none">This is Togglable 1</div>
      <ul>
        <li class="clickable-heading">
          <a href="#">boy</a>
          <div style="display:none">This is Togglable 2</div>
        </li>
        <li class="clickable-heading">
          <a href="#">girl</a>
          <div style="display:none">This is Togglable 3</div>
        </li>
      </ul>
    </li>
  </ul>
</div>
  </div>
  </body>

多个JavaScript切换树状结构

3 个答案: