我正在制作测验应用程序，并使用ArrayList。我的答案有问题：当我只有一个答案时，它就可以工作，但是如果这个问题有两个答案，该怎么办？
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.util.Log;
import android.view.KeyEvent;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.ProgressBar;
import android.widget.TextView;
import java.util.ArrayList;
import cn.pedant.SweetAlert.SweetAlertDialog;
public class MainActivity extends AppCompatActivity {
TextView questionLabel, questionCountLabel, scoreLabel;
EditText answerEdt;
Button submitButton;
ProgressBar progressBar;
ArrayList<QuestionModel> questionModelArraylist;
int currentPosition = 0;
int numberOfCorrectAnswer = 0;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
questionCountLabel = findViewById(R.id.noQuestion);
questionLabel = findViewById(R.id.question);
scoreLabel = findViewById(R.id.score);
answerEdt = findViewById(R.id.answer);
submitButton = findViewById(R.id.submit);
progressBar = findViewById(R.id.progress);
questionModelArraylist = new ArrayList<>();
setUpQuestion();
setData();
submitButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
checkAnswer();
}
});
answerEdt.setOnKeyListener(new View.OnKeyListener() {
public boolean onKey(View v, int keyCode, KeyEvent event) {
// If the event is a key-down event on the "enter" button
Log.e("event.getAction()",event.getAction()+"");
Log.e("event.keyCode()",keyCode+"");
if ((event.getAction() == KeyEvent.ACTION_DOWN) &&
(keyCode == KeyEvent.KEYCODE_ENTER)) {
checkAnswer();
return true;
}
return false;
}
});
}
public void checkAnswer(){
String answerString = answerEdt.getText().toString().trim();
if(answerString.equalsIgnoreCase(questionModelArraylist.get(currentPosition).getAnswer())){
numberOfCorrectAnswer ++;
new SweetAlertDialog(MainActivity.this, SweetAlertDialog.SUCCESS_TYPE)
.setTitleText("Sehr gut!")
.setContentText("Richtig!")
.setConfirmClickListener(new SweetAlertDialog.OnSweetClickListener() {
@Override
public void onClick(SweetAlertDialog sweetAlertDialog) {
currentPosition ++;
setData();
answerEdt.setText("");
sweetAlertDialog.dismiss();
}
})
.show();
}else {
new SweetAlertDialog(MainActivity.this, SweetAlertDialog.ERROR_TYPE)
.setTitleText("Falsch :(")
.setContentText("Die Richtige Antwort ist : "+questionModelArraylist.get(currentPosition).getAnswer())
.setConfirmText("OK")
.setConfirmClickListener(new SweetAlertDialog.OnSweetClickListener() {
@Override
public void onClick(SweetAlertDialog sDialog) {
sDialog.dismiss();
currentPosition ++;
setData();
answerEdt.setText("");
}
})
.show();
}
int x = ((currentPosition+1) * 100) / questionModelArraylist.size();
progressBar.setProgress(x);
}
public void setUpQuestion(){
questionModelArraylist.add(new QuestionModel("Write one planet located between Earth and the sun","Venus or Mercury"));
questionModelArraylist.add(new QuestionModel("the 5th planet from the sun","Jupiter"));
questionModelArraylist.add(new QuestionModel("write names of any two oceans","Atlantic Ocean or Arctic Ocean or Indian Ocean or Pacific Ocean orSouthern Ocean"));
}
public void setData(){
if(questionModelArraylist.size()>currentPosition) {
questionLabel.setText(questionModelArraylist.get(currentPosition).getQuestionString());
scoreLabel.setText("Ergebnis :" + numberOfCorrectAnswer + "/" + questionModelArraylist.size());
questionCountLabel.setText("Frage Nummer : " + (currentPosition + 1));
}else{
new SweetAlertDialog(MainActivity.this, SweetAlertDialog.SUCCESS_TYPE)
.setTitleText("Du bist Fertig :)")
.setContentText("dein Ergebnis ist : "+ numberOfCorrectAnswer + "/" + questionModelArraylist.size())
.setConfirmText("Wiederholen")
.setConfirmClickListener(new SweetAlertDialog.OnSweetClickListener() {
@Override
public void onClick(SweetAlertDialog sDialog) {
sDialog.dismissWithAnimation();
currentPosition = 0;
numberOfCorrectAnswer = 0;
progressBar.setProgress(0);
setData();
}
})
.setCancelText("schließen")
.setCancelClickListener(new SweetAlertDialog.OnSweetClickListener() {
@Override
public void onClick(SweetAlertDialog sDialog) {
sDialog.dismissWithAnimation();
finish();
}
})
.show();
}
}
}
问题课
public class QuestionModel {
public QuestionModel(String questionString, String answer) {
QuestionString = questionString;
Answer = answer;
}
public String getQuestionString() {
return QuestionString;
}
public void setQuestionString(String questionString) {
QuestionString = questionString;
}
public String getAnswer() {
return Answer;
}
public void setAnswer(String answer) {
Answer = answer;
}
private String QuestionString;
private String Answer;
}
如您所见，我想在第一个问题中回答是水星还是金星，第二个问题是木星，而第3个问题有5个答案，“大西洋或北冰洋或印度洋或太平洋或南方海洋” 我该如何使其工作？谢谢。
答案 0 :(得分：1)
基本上：通过更改数据模型。
您会看到，您创建了类来“模拟”现实。如果要允许多个答案，那么简单的一对一映射（就像QuestionModel暗示的那样）根本行不通。然后您的模型应该是1：n，就像1个问题字符串一样，但是答案可能是List<String>。对于只有一个答案的问题，该列表仅包含一个条目。
这就是去那里的方式：首先您先思考如何组织数据，然后构建所有内容，包括围绕它的UI结构。
答案 1 :(得分：0)
@GhostCat是正确的，必须在实施之前进行分析。对于您的特定情况，我认为枚举可能会有所帮助。我对您的目标并不十分清楚，但这就是我最初将如何实现的目标。
并在您的QuestionModel类中将其概括化，我将首先创建一个接口来描述任何可能的答案。
interface AnswerInterface {
val value: String
}
我将使用泛型来扩展此接口，然后我的QuestionModel会变成这样。
class QuestionModel<QuestionAnswer : AnswerInterface>(
var question: String,
vararg answers: QuestionAnswer
)
QuestionAnswer可以是实现AnswerInterface的任何类，而varard意味着我可以具有任意数量的实例作为答案。
考虑到这一点，我的答案列举为：
enum class PlanetAnswers(override val value: String) : AnswerInterface {
VENUS("Venus"),
MERCURY("Mercury"),
JUPITER("Jupiter")
}
最后，一切都像这样联系在一起：
val question1 = QuestionModel("One planet between Earth and Sun?", PlanetAnswers.VENUS, PlanetAnswers.MERCURY)
val question2 = QuestionModel("The 5th planet from the Sun?", PlanetAnswers.JUPITER)
我有一个问题和很多答案，但是它们都必须来自同一枚举。我可以创建更多的枚举，然后创建更多具有不同答案的问题。