Question

我有一个年龄数据： 18,25,36,20,23,21,31，

使用php如何显示此类数据？ 10至20年= 1人，20至30年= 4人，30至40年= 2人

Answer 1

您可以尝试类似的方法。它使用array_map将数据中的所有值除以10（从而将它们分组），然后使用array_count_values来计算每个组中的人数。

$ages = [18,25,36,20,23,21,31];
$groups = array_count_values(array_map(function ($v) { return (int)($v / 10); }, $ages));
for ($i = 0; $i <= max(array_keys($groups)); $i++) {
    echo $i*10 . " to " . ($i*10+9) . " years: " . (isset($groups[$i]) ? $groups[$i]: 0) . "\n";
}

输出：

0 to 9 years: 0 
10 to 19 years: 1 
20 to 29 years: 4 
30 to 39 years: 2

更新

如果您不想显示其中没有人的群组，请改用以下循环：

for ($i = 0; $i <= max(array_keys($groups)); $i++) {
    if (isset($groups[$i])) echo $i*10 . " to " . ($i*10+9) . " years: " . $groups[$i] . "\n";
}

输出：

10 to 19 years: 1 
20 to 29 years: 4 
30 to 39 years: 2

Demo on 3v4l.org

Answer 2

有很多方法，但是我更喜欢直接从mysql查询中获取，

SELECT IF (`age` < 10, '0 to 10 years',
          IF(`age` > 10 AND `age` < 20, '10 to 20 years', 
            IF(`age` > 20 AND `age` < 30, '20 to 30 years', 'more than 30 years')
          )
        ) AS age_group,
        count(*) as `counts`
  FROM `table_name`
  Group by `age_group`

您可以参考此answer来从数据库中存储的DOB中计算年龄

Answer 3

此代码从您的数据库中收集了生日日期，并在所需范围内将它们分组。

//Please update this section to grant access to your database
$username = 'root'; //Your Database Username
$password = ''; //Your Database Password
$database = 'test_sample'; //Your Database Name
$table_name = 'ages'; //Your Table Name
$column_name = 'date_of_birth'; // The Column where the birthday dates can be accessed

$query = 'SELECT `'.$column_name.'` FROM `'.$table_name.'`';
$db_connection = mysqli_connect('localhost', $username, $password, $database);

$result = mysqli_query($db_connection, $query);

$current_ages = [];
$now = new DateTime();
while($data = mysqli_fetch_array($result)) {
    $date = new DateTime($data[$column_name]);
    $interval = $now->diff($date);
    $current_ages[] = $interval->y;
}

// $current_ages = [18,25,36,20,23,21,31];

$desired_range = [
   [10,20], [21,30], [31,40], [41,50]
];

$result = [];
foreach($current_ages as $data) {
  foreach($desired_range as $index => $range) {
    if($data >= $range[0] && $data <= $range[1]) {
       (isset($result[$index]))? $result[$index]++ : $result[$index] = 1;
       break;
    }
  }
}

foreach($desired_range as $index => $range) {
    $count = (isset($result[$index]))? $result[$index] : 0;
    echo $range[0]." to ".$range[1]." years = ".$count.' <br/>';
}

Answer 4

$ages = [18,25,36,20,23,21,31];
$years = array(); // floor range
foreach ($ages as $age)
{
    $m = (int)($age / 10);
    (isset($years[($m*10)])) ? $years[($m*10)]++ : $years[($m*10)] = 1;
}
var_dump($years); // output: array(3) { [10]=> int(1) [20]=> int(4) [30]=> int(2) }

如何显示总数年龄组

4 个答案: