Question

我是C＃的新手。

当前不完整的代码

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace classObjectMethodBasic
{
    public class Program
    {
        static void Main()
        {
            Console.WriteLine("Input a number for first number to do a math on: ");
            int number1 = Convert.ToInt32(Console.ReadLine());

            Console.WriteLine("Input a number for second number to do a math on or you need not enter one: ");
            int number2 = Convert.ToInt32(Console.ReadLine());

            int result1 = new int();
            result1 = Math.math(number1, number2);

            Console.WriteLine("Math result: " + result1);
            Console.ReadLine();
        }
    }
    public class Math
    {
        public static int math(int number1, int number2 = 3)
        {
            int result1 = number1 + number2;
            return result1;
        }
    }
}

需要使第二个参数（number2）为可选。在当前代码中，如果我运行它但未输入int number2的值（意味着仅按回车键），则程序会退出，但会出现异常。异常错误：

System.FormatException: 'Input string was not in a correct format.'

我如何使程序将第二个参数作为可选参数使用？

谢谢，杰瑞

Answer 1

更改代码以验证收到的输入会更好。在您的情况下，您可能没有输入第二个值的值，请参见下面的更正

    static void Main()
    {
        Console.WriteLine("Input a number for first number to do a math on: ");
        int number1 = 0;
        string input1 = Console.ReadLine();
        if (!Int32.TryParse(input1, out number1))
        {
            Console.WriteLine("Number 1 was entered incorrectly");
            Console.ReadLine();
            return;
        }


        Console.WriteLine("Input a number for second number to do a math on or you need not enter one: ");
        int number2 = 0;
        string input2 = Console.ReadLine();


        if (input2.Equals(string.Empty))
        {
            Console.WriteLine("Math result: " + Math.math(number1));
        }
        else
        {
            if (!Int32.TryParse(input2, out number2))
            {
                Console.WriteLine("Number 2 was entered incorrectly");
                Console.ReadLine();
                return;
            }
            else
            {
                Console.WriteLine("Math result: " + Math.math(number1, number2));
            }
        }

        Console.ReadLine();
    }

Answer 2

您已经声明第二个参数为可选。该错误是由于以下代码行引起的：

 int number2 = Convert.ToInt32(Console.ReadLine());

您可以修改代码以在调用Math.math()函数之前检查两个参数，或者像这样传递两个参数：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace classObjectMethodBasic
{
    public class Program
    {
        static void Main()
        {
            Console.WriteLine("Input a number for first number to do a math on: ");
            string input1 = Console.ReadLine();
            int number1 = 0;
            int.TryParse(input1, out number1);

            Console.WriteLine("Input a number for second number to do a math on or you need not enter one: ");
            string input2 = Console.ReadLine();
            int number2 = 0;
            int.TryParse(input2, out number2);

            int result1 = new int();
            result1 = Math.math(number1, number2);

            Console.WriteLine("Math result: " + result1);
            Console.ReadLine();
        }
    }
    public class Math
    {
        public static int math(int number1, int number2 = 3)
        {
            int result1 = number1 + number2;
            return result1;
        }
    }
}

C＃方法第二个参数可选

2 个答案: