如果要通过INNER JOIN选择数据库但2 ON且OR之间为ON的SQL脚本。
这是我的错误脚本
SELECT *
FROM user
INNER JOIN friend ON friend.id1_friend = user.id_user
OR ON friend.id2_friend = user.id_user
WHERE id_user != '$_SESSION[user]'
AND friend_status != '2'
ORDER BY id_user DESC
答案 0 :(得分:1)
在一张桌子上使用一次。您刚放完或处于其他情况。
SELECT*FROM user
INNER JOIN friend ON
(friend.id1_friend=user.id_user OR friend.id2_friend=user.id_user)
WHERE id_user != $_SESSION[user]
AND friend_status != '2'
ORDER BY id_user DESC
答案 1 :(得分:1)
SELECT * -- this is not smart
FROM user u
JOIN friend f
ON u.id_user IN(f.id1_friend,f.id2_friend)
WHERE u.id_user != '$_SESSION[user]' -- this is not safe
AND f.friend_status != 2
ORDER
BY u.id_user DESC