Question

有人可以告诉我为什么不画图吗？

当我有3片时，它绘制得很好。但是当我添加第四个切片时，它不再绘制了。

代码：

function pieChart() {



            var data = new google.visualization.DataTable();
            data.addColumn('string', 'Placement');
            data.addColumn('number', 'Amount');
            data.addColumn({type: 'string', role: 'tooltip'});
            data.addRows([
                <?php  
                echo "['1st Place', $first_total, '1st place Received: $first_total times'],";
                echo "['2nd Place', $second_total, '2nd place Received: $second_total times'],";
                echo "['3rd Place', $third_total, '3rd place Received: $third_total times']";

//WHEN I ADD THIS BOTTOM LINE THE CHART NO LONGER DRAWS
                echo "['4th Place', $fourth_total, '4th place Received: $fourth_total times']";

                ?>
            ]);

            var options = {
                tooltip: {isHtml: true},
               // 'title':'Number of times Dancer Placed in top 3 ranks',
                focusTarget: 'category',
                'legend': { position: 'bottom' },
                //'slices': {0: {color: '#D4AF37'}, 1:{color: '#C0C0C0'}, 2:{color: '#CD7F32'}}
            };


            var chart = new google.visualization.PieChart(document.getElementById('pie_chart'));
            chart.draw(data, options);
        }

编辑

我确实尝试了此代码，而不使用php和hardcoding值。结果是相同的，它将与前三个切片一起绘制，但是当我添加第四个切片时，它将不再绘制。

Answer 1

第三行中的数组后需要一个逗号...

echo "['3rd Place', $third_total, '3rd place Received: $third_total times'],"; // <-- add comma after array

Google饼图未绘制

1 个答案: