Question

图像显示错误：java.lang.StringIndexOutOfBoundsException 开始0，结束-1，长度614998

当我用不同的名称多次复制相同的变量时。它告诉我这个错误。我只能插入一张图片

Fileupload.jsp

<form enctype="multipart/form-data" action="/Kastamandap/Admin/Controller/uploadFile.jsp" method="post">
    <H1>choose the file to upload</H1><hr>

    <input name="file"  type="file">
    <input name="file2"  type="file">
    <input name="file3"  type="file">
    <input name="file4"  type="file">
    <input type="submit" class="btn btn-primary" value="upload">
 </form>

在uploadFile.jsp

中

//对于图像1

 <%@ page import="java.sql.*,java.io.*,java.util.zip.*,java.lang.*" %>
<%
String saveFile = "";

File ff = null;
String contentType = request.getContentType();
if ((contentType != null) && contentType.indexOf("multipart/form-data") >= 0) {
    DataInputStream in = new DataInputStream(request.getInputStream());
    int formDataLength = request.getContentLength();
    byte dataBytes[] = new byte[formDataLength];
    int byteRead = 0;
    int totalBytesRead = 0;
    while (totalBytesRead < formDataLength) {
        byteRead = in.read(dataBytes, totalBytesRead, formDataLength);
        totalBytesRead += byteRead;
    }
    String file = new String(dataBytes);
    saveFile = file.substring(file.indexOf("filename=\"") + 10);
    saveFile = saveFile.substring(0, saveFile.indexOf("\n"));
    saveFile = saveFile.substring(saveFile.lastIndexOf("\\") + 1, saveFile.indexOf("\""));
    int lastIndex = contentType.lastIndexOf("=");
    String boundry = contentType.substring(lastIndex + 1, contentType.length());
    int pos;
    pos = file.indexOf("filename=\"");
    pos = file.indexOf("\n", pos) + 1;
    pos = file.indexOf("\n", pos) + 1;
    pos = file.indexOf("\n", pos) + 1;
    int boundaryLocation = file.indexOf(boundry, pos) - 4;
    int startPos = ((file.substring(0, pos)).getBytes()).length;
    int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length;

    ff = new File("D:/programmming/JAVA/eclipse-workspace/Kastamandap/WebContent/Images/" + saveFile);
    FileOutputStream fileOut = new FileOutputStream(ff);
    fileOut.write(dataBytes, startPos, (endPos - startPos));
    fileOut.flush();
    fileOut.close();

        %>

     //Image 1 is successfully inserted

相同的代码，但它向我显示此错误，请帮我注释一下错误部分

      <%
      String saveFile3 = "";
     File ff3 =  null;
     String contentType3 = request.getContentType();
    if((contentType3 != null) && contentType3.indexOf("multipart/form-data") >= 0 ) {
DataInputStream in3 = new DataInputStream(request.getInputStream());
int formDataLength3 = request.getContentLength();
byte dataBytes3[] = new byte[formDataLength3];
int byteRead3 = 0;
int totalBytesRead3=0;
while(totalBytesRead3 < formDataLength3) {byteRead3=in3.read(dataBytes3,totalBytesRead3,formDataLength3);
    totalBytesRead3 += byteRead3;
}
String file3 = new String(dataBytes3);
saveFile3 = file3.substring(file3.indexOf("filename=\"")+10); 

    //From here it is showing java.lang.StringIndexOutOfBoundsException

    saveFile3 = saveFile3.substring(0, saveFile3.indexOf("\n"));

    saveFile3 = saveFile3.substring(saveFile3.lastIndexOf("\\") + 1,       saveFile3.indexOf("\""));
    int lastIndex3 = contentType3.lastIndexOf("=");
    String boundry3 = contentType3.substring(lastIndex3 + 1,    contentType3.length());
    int pos3;
    pos3 = file3.indexOf("filename=\"");
    pos3 = file3.indexOf("\n", pos3) + 1;
    pos3 = file3.indexOf("\n", pos3) + 1;
    pos3 = file3.indexOf("\n", pos3) + 1;
    int boundaryLocation3 = file3.indexOf(boundry3, pos3) - 4;
    int startPos3 = ((file3.substring(0, pos3)).getBytes()).length;
    int endPos3 = ((file3.substring(0,    boundaryLocation3)).getBytes()).length;

     ff3 = new File("D:/programmming/JAVA/eclipse-workspace/Kastamandap/WebContent/Images/"+saveFile3);
    FileOutputStream fileOut3 = new FileOutputStream(ff3);
    fileOut3.write(dataBytes3, startPos3, (endPos3 - startPos3));
    fileOut3.flush();
    fileOut3.close();

    }

Answer 1

如何从jsp上传多个文件？

将相关的jar文件添加到lib或maven依赖项。

index.jsp

 <html>
<head></head>
<body>
    <form action="UploadServlet" method="post" enctype="multipart/form-data">
        Select File to Upload:<input type="file" name="fileName"
            multiple="multiple" /> <br> <input type="submit" value="Upload" />
    </form>
</body>
</html>

UploadServlet.java

import java.io.File;
import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.apache.commons.fileupload.servlet.ServletFileUpload;

import com.oreilly.servlet.multipart.FilePart;
import com.oreilly.servlet.multipart.MultipartParser;

@WebServlet("/UploadServlet")
public class UploadServlet extends HttpServlet {
    private static final long serialVersionUID = 1L;

    public UploadServlet() {
        // TODO Auto-generated constructor stub
    }

    protected void doGet(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        doPost(request, response);
    }

    protected void doPost(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        try {
            String path1 = "F:\\Temp\\";
            boolean isMultipart = ServletFileUpload.isMultipartContent(request);
            if (isMultipart) {
                MultipartParser parser = new MultipartParser(request, 1024 * 1024 * 1024); /* file limit size of 1GB */
                com.oreilly.servlet.multipart.Part _part;
                while ((_part = parser.readNextPart()) != null) {
                    if (_part.isFile()) {
                        FilePart fPart = (FilePart) _part; // get some info about the file
                        String name = fPart.getFileName();
                        if (name != null) {
                            fPart.writeTo(new File(path1 + File.separator + name));

                        }
                    }
                }
            }
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

如何使用jsp

1 个答案: