Question

因此，我一直在创建一个可以在在线购物站点中收藏商品的用户数据库。即使当我输入b.title和board时，它们似乎都打印“ u'board name'”，我似乎还是收到了此错误。应该这样，以便当某人选中“董事会”复选框时，该服装与董事会的关系应添加到数据库中。

<form action="" method="POST" name="boards_list">
          <table class="table is-striped">
            {% for board in boards %}
            <tr>
              <td>
                <label class="checkbox">
                  <input type="checkbox" name="board_titles" value="{{board.title}}"/>
                </label>
                <a href="#">{{board.title}}</a>
              </td>
            </tr>
            {% endfor %}
          </table>

          <div class="field is-grouped">
            <div class="control">
              <button type="submit" class="button is-small">Add To Favs</button>
            </div>
          </div>
        </form>

这是上面显示的Jinja2模板中的代码。以下是源代码：

if request.method =="POST":
            f_b_titles = request.form.getlist("board_titles")
            clothing = Clothing.query.filter_by(name = name).first()
            userid = int(current_user.id)
            clothingid = int(clothing.id)
            for b in boards:
                for board in f_b_titles:
                    if b.title == board:
                        fav_relationship = Favourites_relationship(user_id = userid, clothing_id = clothingid, favs_board = b.title)
                        db.session.add(fav_relationship)
                        db.session.commit()
                        flash('Added favourite to mood board!', 'success')

最后，来自数据库模型的代码：

class Favourites_relationship(db.Model, UserMixin):
id = db.Column(db.Integer, primary_key=True)
user_id = db.Column(db.Integer, db.ForeignKey('user.id'), unique=True, nullable=False)
clothing_id = db.Column(db.Integer, db.ForeignKey('clothing.id'),nullable=False)
board_title = db.Column(db.Unicode, db.ForeignKey('favourites_board.title'), nullable=False)

和：

class Favourites_board(db.Model, UserMixin):
id = db.Column(db.Integer, primary_key=True)
title = db.Column(db.String(100), nullable=False)
user_id = db.Column(db.Integer, db.ForeignKey('user.id'), nullable=False)
favourites_relationships = db.relationship('Favourites_relationship', backref='favs_board', lazy=True)

有关错误的更多信息：

return self.wsgi_app(environ, start_response)

File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/flask/app.py", line 2295, in wsgi_app
response = self.handle_exception(e)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/flask/app.py", line 1741, in handle_exception
reraise(exc_type, exc_value, tb)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/flask/app.py", line 2292, in wsgi_app
response = self.full_dispatch_request()
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/flask/app.py", line 1815, in full_dispatch_request
rv = self.handle_user_exception(e)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/flask/app.py", line 1718, in handle_user_exception
reraise(exc_type, exc_value, tb)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/flask/app.py", line 1813, in full_dispatch_request
rv = self.dispatch_request()
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/flask/app.py", line 1799, in dispatch_request
return self.view_functions[rule.endpoint](**req.view_args)
File "/Users/leawhitelaw/Desktop/online_shop_data/flaskshop/routes.py", line 97, in product_details
fav_relationship = Favourites_relationship(user_id = userid, clothing_id = clothingid, favs_board = b.title)

Answer 1

尝试

fav_relationship = Favourites_relationship(user_id = userid, clothing_id = clothingid, favs_board = b)

基本上，该错误表示您只能将Favourites_board个实例（例如fb = Favourites_board()）分配给某个关系。

因此，假设木板是Favourites_board实例的列表，您只需将清单中的木板（b）分配给favs_board=...。

Answer 2

board_title = db.Column(db.Unicode, db.ForeignKey('favourites_board.title'), nullable=False)

这行是错误的

来自here

使用Unicode类型时，仅适合传递Python unicode对象，而不是纯str。如果在下面传递了一个普通的str Python 2发出警告。如果您注意到自己的申请发出这些警告，但您不确定它们的来源， Python警告过滤器，记录在 http://docs.python.org/library/warnings.html，可用于转向这些警告变成异常，将说明堆栈跟踪：

由于您要从表单传递原始值，因此需要python对象。

尝试使用：

db。字符串

db.Text

或db.Unicodetext

SQL Alchemy AttributeError：“ unicode”对象没有属性“ _sa_instance_state”

2 个答案: