我需要使用map创建一个JSON数组。
package main
import "fmt"
func main(){
id := [5]string{"1","2","3","4","5"}
name := [5]string{"A","B","C","D","E"}
parseData := make(map[string]string)
for counter,_ := range id {
parseData["id"] = id[counter]
parseData["name"] = name[counter]
fmt.Println(parseData)
}
}
我当前的输出:
map[id:1 name:A]
map[id:2 name:B]
map[id:3 name:C]
map[id:4 name:D]
map[id:5 name:E]
我需要如下所示的JSON输出:
[{id:1, name:A},
{id:2, name:B},
{id:3, name:C},
{id:4, name:D},
{id:5, name:E}]
我了解使用map的基础知识,它是用于key:value对的字典。如何使用map实现JSON输出。
答案 0 :(得分:6)
要通过地图创建JSON
的数组,您需要将一个map
创建为slice
,将另一个package main
import (
"fmt"
"encoding/json"
)
func main(){
id := [5]string{"1","2","3","4","5"}
name := [5]string{"A","B","C","D","E"}
parseData := make([]map[string]interface{}, 0, 0)
for counter,_ := range id {
var singleMap = make(map[string]interface{})
singleMap["id"] = id[counter]
singleMap["name"] = name[counter]
parseData = append(parseData, singleMap)
}
b, _:= json.Marshal(parseData)
fmt.Println(string(b))
}
创建为单个地图,然后在单个地图中一个接一个地分配值,然后追加将其放入地图切片中,例如遵循以下代码:
JSON
您还可以在here上进行测试
它将[{"id":"1","name":"A"},
{"id":"2","name":"B"},
{"id":"3","name":"C"},
{"id":"4","name":"D"},
{"id":"5","name":"E"}]
打印为:
{{1}}
答案 1 :(得分:2)
对我来说,这更像是一个对象数组。您可以这样获得所需的输出:
type data struct {
Id string
Name string
}
func main(){
id := [5]string{"1","2","3","4","5"}
name := [5]string{"A","B","C","D","E"}
var parsedData []data
for counter := range id {
parsedData = append(parsedData, data{Name: name[counter], Id: id[counter]})
}
bytes, _ := json.Marshal(parsedData)
fmt.Print(string(bytes))
}
输出应如下所示:
[
{"Id":"1","Name":"A"},
{"Id":"2","Name":"B"},
{"Id":"3","Name":"C"},
{"Id":"4","Name":"D"},
{"Id":"5","Name":"E"}
]