Question

我需要python 2.7的帮助，需要使用命令“ urllib2.Request”从本地Web服务器读取数据只要服务器是可访问的（192.168.5.44），我就使用代码（在下面附上）并且可以正常工作。如果服务器不可用，则代码会停止并显示错误

public class MessageQuery : ObjectGraphType<Message>
{
    public MessageQuery()
    {
        Field(o => o.Content).Resolve(o => "This is Content").AuthorizeWith("Authorized");
        Field(o => o.SentAt);
        Field(o => o.Sub).Resolve(o => "This is Sub");
    }
}

我应该在代码中添加些什么，以便在发生错误的情况下继续运行并增加read的值（例如N / A或其他内容。....）我有几个这样的服务器，如果一台服务器宕机，一切都会停止。

我的代码：

select po.Product from products po inner join
    (
    select pr.product,pr.Period,pr.Price from products pr inner join
        (
        select product,max(period)as [period] from products
        group by product
        ) mx on mx.Product = pr.Product and mx.period = pr.Period
    ) mxx on mxx.Product = po.Product 
and po.Period = mxx.Period-1
and mxx.Price <> po.Price

Answer 1

使用try和except块来避免由于任何错误而停止程序，如下所示：

try:
    request = urllib2.Request("http://192.168.5.44")
    fip44 = urllib2.urlopen(request)
    time.sleep(1)
    sip44 = fip44.read()

    def beri44( sip44, first, last ):
        start = sip44.index( first ) + len( first )
        end = sip44.index( last, start )
        return sip44[start:end]

    jed = float (beri44( sip44, "[", "]" ))
    fjed = open("/var/www/html/Temp/jed.txt", "w")
    fjed.write(str(jed))      
    fjed.close()
    print"jed:", jed
except:
    # Do whatever you want here in the case of an error occurred
    pass

希望有帮助。

Python 2.7忽略URLError：<urlopen error =“” [errno =“” 113] =“” no =“” route =“” to =“” host =“”>

1 个答案: