Question

这个问题与电话信息有关，而我正在使用Genesys http://www.genesyslab.com，但我更喜欢在这里发帖提问，因为这是一个与SQL相关的问题。我有两张桌子：

（表1：“ CallerID ”）一个包含CallerID和ConnID的表（标识一个调用）。 （表2：“ Callinfo ”）另一个表包含CallerID，呼入日期（以int格式存储，带有翻译它的方式）和状态行，它对应于我将在下面解释的动作。一个示例行是

ConnID                StartTime   Status
--------------------- ----------- -----------
30119914212527698     1300286888  2

每次呼叫进入两个表都会更新。我需要做的是从Callinfo获取状态为2或4的最后两天（这些是未回答的呼叫）的所有呼叫，并从CallerID表中获取CallerID。之后，我需要检查相同的CallerID是否在其ConnID的Callinfo表检查中有新的寄存器。如果这些新寄存器的状态不同于2 o 4（意味着通信成功），我应该删除第一个查询的CallerID。

查询的目的是调用那些在过去两天内尝试调用但未能调用的客户端。

第一个查询正常，你应该忽略DATEDIFF函数。

DECLARE @twoDays BIGINT
SET @twoDays = 172800   --48hs expressed in seconds

SELECT DISTINCT ConnID, StartTime, CID.CallerID, Status FROM Callinfo
INNER JOIN dbo.CallerID CID
    ON Callinfo.ConnID = CID.ConnID
WHERE 
    (Status = 2 OR Status = 4)
    AND 
    StartTime > DATEDIFF(second, '1970-01-01 00:01:00', GETUTCDATE())- @twoDays

我不知道如何使用结果并检查是否存在状态不同为2和4的新呼叫。

我正在研究SQL Server 2005。

以下序列可以清除：如果调用者A的情况如此：

1/1 12pm: A call OK 
1/1 1pm: A call FAIL

然后我应该得到结果。但如果情况是这样的话：

1/1 12pm: A call OK 
1/1 1pm: A call FAIL 
2/1 12pm: A call OK

然后我不应该得到A作为结果。因此，当我检查3/1时，我不会得到结果，因为A的最后一次呼叫是正常的，并且在4/1呼叫者A不应该出现在第一次查询中。

Answer 1

这样的事情应该更快。

DECLARE @twoDaysAgo DateTime
SET @twoDaysAgo = DATEADD(day,-2,GETDATE())

WITH MissedCalls AS
(
  SELECT DISTINCT ConnID, StartTime, CID.CallerID, Status FROM Callinfo
  JOIN dbo.CallerID CID ON Callinfo.ConnID = CID.ConnID
  WHERE Status IN (2,4)
    AND StartTime > @twoDaysAgo
), NotMissedCalls AS
(
   SELECT DISTINCT ConnID, StartTime, CID.CallerID, Status 
   FROM Callinfo
   JOIN dbo.CallerID CID ON Callinfo.ConnID = CID.ConnID
   WHERE Status not in (2,4)
    AND StartTime > @twoDaysAgo
    -- following line may speed up or slow down depending on table sizes and indexes
    AND CID.CallerID in (SELECT CALLERID FROM MissedCalls)
)
SELECT *
FROM MissedCalls
WHERE NOT CallerID IN (SELECT CallerID FROM NotMissedCalls)

注意：我没有测试，所以我可能有错字。为了安全起见，我为所有查询添加了所有列，但我希望这可以改进。（较少的列应该稍快一点。）

这解决了新问题。

DECLARE @twoDaysAgo DateTime
SET @twoDaysAgo = DATEADD(day,-2,GETDATE())

WITH MissedCalls AS
(
  SELECT ConnID, Max(StartTime) as LastFailDate, CID.CallerID  FROM Callinfo
  JOIN dbo.CallerID CID ON Callinfo.ConnID = CID.ConnID
  WHERE Status IN (2,4)
    AND StartTime > @twoDaysAgo
  GROUP BY ConnID, CID.CallerID
), NotMissedCalls AS
(
   SELECT ConnID,Max(StartTime) as LastGoodDate,CID.CallerID 
   FROM Callinfo
   JOIN dbo.CallerID CID ON Callinfo.ConnID = CID.ConnID
   WHERE Status not in (2,4)
    AND StartTime > @twoDaysAgo
    -- following line may speed up or slow down depending on table sizes and indexes
    AND CID.CallerID in (SELECT CALLERID FROM MissedCalls)
   GROUP BY ConnID, CID.CallerID
), CallList AS
(
   SELECT LastFailDate, LastGoodDate, Bad.ConnID, Bad.CallerID
   FROM MissedCalls Bad
   JOIN NotMissedCalls Good ON Bad.ConnID = Good.ConnID AND Bad.CallerID = Good.CallerID
)
SELECT LastFailDate, ConnID, CallerID
FROM CallList
WHERE (LastGoodDate > LastFailDate) OR (LastGoodDate IS NULL)

Answer 2

我想我有一个工作基地。

DECLARE @twoDays BIGINT
SET @twoDays = 172800   --48hs expressed in seconds

SELECT DISTINCT ConnID, StartTime, CID.CallerID, Status FROM Callinfo
INNER JOIN dbo.CallerID CID
    ON Callinfo.ConnID = CID.ConnID
WHERE 
    (Status = 2 OR Status = 4)
    AND 
    StartTime > DATEDIFF(second, '1970-01-01 00:01:00', GETUTCDATE())- @twoDays
    AND CID.CallerID NOT IN (
        SELECT DISTINCT CID.CallerID FROM Callinfo
        INNER JOIN dbo.CallerID CID
        ON Callinfo.ConnID = CID.ConnID
        WHERE 
            (Status <> 2 AND Status <> 4)    
        AND 
            StartTime > DATEDIFF(second, '1970-01-01 00:01:00', GETUTCDATE())- @twoDays
        )

此查询将在第二个查询中显示时删除callerID：也就是说在过去2天内设置了呼叫的呼叫者。

缺陷：无法检测A是否呼叫第1天，召回第2天并且失败（范围是第1天到第3天）。但是当你在第2天到第4天尝试时，他会在下次检查时加注。

使用SQL结果进行新查询

2 个答案: