Question

我有这个if语句

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script>
    $(document).ready(function () {

        $(document).on('submit', '#rentform', function () {
            var data = $(this).serialize()

            $.ajax({
                type: 'POST',
                url: 'newrent.php',
                data: data,
                success:(
                    function (data){$(".result").html(data)}

                )
            });
            return false;
        });
    } )

    $(document).ready(function () {
        $('#rent').change(function(){
            var x =($('#rent option:selected').data('sireal'))
            $('#itemsn').val(x);
        });
    } )
</script>


<form method="post" id="rentform" action="" novalidate="novalidate">
    <label for="item">REnter Name</label>
    <select name="rnt_name" id="name_rent">
        <option selected disabled>SELECT Renter Name</option>
        <?php foreach ($nameq as $res) : ?>
            <option value="<?= $res['user_name']?>"><?= $res['user_name'] ?></option>
        <?php endforeach; ?>
    </select>
    <br/>
    <br/>

    <label for="item">Cameras</label>
    <select name="item" id="rent">
        <option selected disabled>SELECT ITEM</option>
<?php foreach ($rentq as $row) : ?>
    <option value="<?= $row['item_brand']?>" data-sireal="<?= $row['s_n'] ?>"><?= $row['item_brand'] ?></option>
   <?php endforeach; ?>
    </select><br/>
    <br/>
<input type="hidden" name="sn" id="itemsn" value="">
    <label name="from_date">RENT FROM</label>
    <input type="date" name="from_date"><br/>
    <label name="from_hour">RENT FROM Hour</label>
    <input type="time" name="from_hour"><br/>
    <label name="to_date">RENT TO</label>
    <input type="date" name="to_date"><br/>
    <label name="to_hour">RENT FROM Hour</label>
    <input type="time" name="to_hour"><br/>
<input type="submit" name="submit" value="Send Rent">
</form>

<div class="result">

</div>

if($_POST){

 $name = $_POST['rnt_name'];
 $item = $_POST['item'];
 $fdate = $_POST['from_date'];
 $fhour = $_POST['from_hour'];
 $tdate = $_POST['to_date'];
 $thour = $_POST['to_hour'];
 $sn = $_POST['sn'];


 $csheck = "SELECT * FROM rent";
 $ckq = mysqli_query($link,$csheck);

    foreach ($ckq as $res) {}

   $count = "SELECT item_brand = '$item',s_n = '$sn',COUNT(*)
FROM item
WHERE status = 1 AND item_brand = '$item' AND s_n = '$sn'";
    $cnt = mysqli_query($link,$count);
 foreach ($cnt as $itm);

$itmq = "SELECT rent_item = '$item',COUNT(*)
FROM rent ";
$itemres = mysqli_query($link,$itmq);

foreach ($itemres as $missitm){};

if(($fdate >= $res['rent_from_d'] && $res['rent_to_d'] >= $tdate && $missitm['COUNT(*)'] >= $itm['COUNT(*)']   ) || ($fdate > $res['rent_from_d'] && $res['rent_to_d'] > $tdate && $fdate > $res['rent_from_d'] || $fdate <= $res['rent_to_d'] && $fhour <= $res['rent_to_t'] && $missitm['COUNT(*)'] >= $itm['COUNT(*)'] ) )  {
    echo 'no good Item Rented To '.$res['renter'] ;

 }else{
     $newrent = "INSERT INTO rent (renter,rent_item,rent_from_d,rent_from_t,rent_to_d,rent_to_t) 
VALUES ('$name','$item','$fdate','$fhour','$tdate','$thour')";
     mysqli_query($link,$newrent);

    echo 'pass';

 }

这是表单提交后我在数据库中得到的内容

rent_id renter  rent_item   sn  rent_from_d rent_from_t rent_to_d   rent_to_t
115    dror        x70     1234 2018-11-29  10:00     2018-11-29    14:00

我想做的是创建一个租金系统。我的问题是如何验证是否在两个日期和时间之间选择了项目。每次创建新的租金时，已选择的特定项目的状态都设置为0，因此该系统将不再可用。

谢谢。

检查日期和时间之间的验证

0 个答案: