Question

我使用Javaparser（来自javaparser.org）和javasymbolsolver来解析Java。

我有一个访问File.separator的简单Java源代码（请参见源代码中的多行字符串）；我希望我的程序打印java.io.File.fileseparator。相反，它打印File.separator，我得到UnsolvedSymbolException{context='File', name='Solving File'}；然后打印System.out，我得到UnsolvedSymbolException{context='System', name='Solving System'}。

@Test
public void parserTest() {
    CombinedTypeSolver combinedTypeSolver = new CombinedTypeSolver();
    combinedTypeSolver.add(new ReflectionTypeSolver());
    JavaSymbolSolver symbolSolver = new JavaSymbolSolver(combinedTypeSolver);
    JavaParser.getStaticConfiguration().setSymbolResolver(symbolSolver);

    CompilationUnit compilationUnit = JavaParser.parse(
            "import java.io.File;\n" +
            "\n" +
            "public class Main {\n" +
            "    static String s = File.separator;\n" +
            "    public static void main(String args[]) {\n" +
            "        System.out.println(s);\n" +
            "    }\n" +
            "}\n");
    compilationUnit.accept(
            new ModifierVisitor<Void>() {
                @Override
                public Visitable visit(final FieldAccessExpr n, final Void arg) {
                    System.out.println(n);
                    try { // this does not work!!!
                        System.out.println(n.getScope().calculateResolvedType());
                    } catch (Exception e) {
                        e.printStackTrace();
                    }

                    return super.visit(n, arg);
                }
            },
            null
    );
}

据我了解，在Java Symbol Solver的某个深处，它试图将File解析为一个值，当然会失败。

如何获取字段的标准名称？

Answer 1

更新到3.8.0 后，将执行以下操作：

ResolvedType resolvedType = n.getScope().calculateResolvedType();
System.out.println(resolvedType.describe());

JavaSymbolSolver：获取文件的全限定名称

1 个答案: